How to Solve Logarithmic Equations? (+FREE Worksheet!)

In this blog post, you will learn how to solve Logarithmic Equations using the properties of logarithms in a few easy steps.

How to Solve Logarithmic Equations? (+FREE Worksheet!)
Tutor-style math help

Solve Logarithmic Equations: what to notice and how to work it

Logarithms skill
A logarithm is an exponent question written backward. Before using log rules, translate the statement into the power it is asking about.

What to notice first

Identify the base and the input. The input of a logarithm must be positive in real-number work.

Common student mistake

Do not split a sum inside a logarithm. \(\log_b(M+N)\) is not \(\log_b M+\log_b N\).

Key formulas and cues

\(\log_b(x)=y\Leftrightarrow b^y=x\)
\(\log_b(MN)=\log_b M+\log_b N\)
\(\log_b(M^p)=p\log_b M\)
\(\log_b(x-h)\text{ needs }x>h\)
vertical asymptote

A reliable path

  1. Translate firstAsk: the base to what power gives the input?
  2. Use rules legallyProducts, quotients, and powers have rules; sums do not split.
  3. Protect the domainKeep the log input positive and track asymptotes when graphing.

Worked examples

Evaluate a log

Example: \(\log_3(81)\)
  1. Ask 3 to what power equals 81.
  2. 3 to the fourth power is 81.
  3. The logarithm is that exponent.
Answer: \(4\)

Find a log domain

Example: \(y=\log_2(x-5)\)
  1. The input is x – 5.
  2. Require x – 5 > 0.
  3. Solve the inequality.
Answer: \(x>5\)
Try one before moving on
Try: Evaluate \(\log_4(64)\).
Answer: \(3\), because \(4^3=64\).
Next step: do the matching worksheet or quiz while the method is still fresh, then come back and explain the first step in your own words.

Related Topics

Step-by-step guide to solving logarithmic equations

  • Convert the logarithmic equation to an exponential equation when it’s possible. (If no base is indicated, the base of the logarithm is \(10\))
  • Condense logarithms if you have more than one log on one side of the equation.
  • Plug the answers back into the original equation and check if the solution works.

For education statistics and research

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Logarithmic Equations – Example 1:

Find the value of the variables in each equation. \(\log_{4}{(20-x^2)}=2\)

Solution:

Use log rule: \(\log_{b}{x}=\log_{b}{y}\), then: \(x=y\)

\(2=\log_{4}{4^2},\log_{4}{(20-x^2)}=\log_{4}{4^2}=\log_{4}{16}\)

then: \(20-x^2=16→20-16=x^2→x^2=4→x=2\) or \(x=-2\)

Logarithmic Equations – Example 2:

Find the value of the variables in each equation. \(log⁡(2x+2)=log⁡(4x-6)\)

Solution:

When the logs have the same base: \(f(x)=g(x)\),then: \(ln(f(x))=ln(g(x))\),

\(log⁡(2x+2)=log⁡(4x-6)→2x+2=4x-6→2x+2-4x+6=0\)

\(2x+2-4x+6=0→-2x+8=0→-2x=-8→x=\frac{-8}{-2}=4\)

Logarithmic Equations – Example 3:

Find the value of the variables in each equation. \(\log_{2}{(25-x^2)}=2\)

Solution:

Use log rule: \(\log_{b}{x}=\log_{b}{y}\), then: \(x=y\)

\(2=\log_{2}{2^2},\log_{2}{(25-x^2)}=\log_{2}{2^2}=\log_{2}{4}\)

Then: \(25-x^2=4→25-4=x^2→x^2=21 →x=\sqrt{21} \) or \(-\sqrt{21}\)

Logarithmic Equations – Example 4:

Find the value of the variables in each equation. \(log⁡(8x+3)=log⁡(2x-6)\)

Solution:

When the logs have the same base: \(f(x)=g(x)\),then: \(ln(f(x))=ln(g(x))\),

\(log⁡(8x+3)=log⁡(2x-6)→8x+3=2x-6→8x+3-2x+6=0\)

\(6x+9=0→6x=-9→x=\frac{-9}{6}=-\frac{3}{2}\)
Logarithms of negative numbers are not defined. Therefore, there is no solution for this equation.

Exercises for Logarithmic Equations

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Find the value of the variables in each equation.

  1. \(\color{blue}{log⁡(x+5)=2}\)
  2. \(\color{blue}{log x-log 4=3}\)
  3. \(\color{blue}{log x+log 2=4}\)
  4. \(\color{blue}{log 10+log x=1}\)
  5. \(\color{blue}{log x+log 8=log 48}\)
  6. \(\color{blue}{-3\log_{3}{(x-2)}=-12}\)
  7. \(\color{blue}{log 6x=log (x+5)}\)
  8. \(\color{blue}{log (4k-5)=log (2k-1)}\)
Answer 3

Answers

  1. \(\color{blue}{95}\)
  2. \(\color{blue}{4000}\)
  3. \(\color{blue}{5000}\)
  4. \(\color{blue}{1}\)
  5. \(\color{blue}{6}\)
  6. \(\color{blue}{83}\)
  7. \(\color{blue}{1}\)
  8. \(\color{blue}{2}\)

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