# Pre-Algebra Practice Test Questions

Preparing for the Pre-Algebra Math test? Try these free Pre-Algebra Math Practice questions. Reviewing practice questions is the best way to brush up on your Math skills. Here, we walk you through solving 10 common Pre-Algebra Math practice problems covering the most important math concepts on the Pre-Algebra Math test.

These Pre-Algebra Math practice questions are designed to be similar to those found on the real Pre-Algebra Math test. They will assess your level of preparation and will give you a better idea of what to study for your exam.

$14.99 Satisfied 92 Students ## 10 Sample Pre-Algebra Math Practice Questions 1- Jason needs a score of 75 average in his writing class to pass. On his first 4 exams, he earned scores of 68, 72, 85, and 90. What is the minimum score Jason can earn on his fifth and final test to pass?_________ 2- Anita’s trick–or–treat bag contains 12 pieces of chocolate, 18 suckers, 18 pieces of gum, 24 pieces of licorice. If she randomly pulls a piece of candy from her bag, what is the probability of her pulling out a piece of sucker? A. $$\frac{1}{3}$$ B. $$\frac{1}{4}$$ C. $$\frac{1}{6}$$ D. $$\frac{1}{12}$$ 3- What is the perimeter of a square in centimeters that has an area of 595.36 cm$$^2$$? A. 97.2 B. 97.6 C. 97.7 D. 97.9 4- The perimeter of a rectangular yard is 60 meters. What is its length if its width is twice its length? A. 10 meters B. 18 meters C. 20 meters D. 24 meters 5- The average of 6 numbers is 12. The average of 4 of those numbers is 10. What is the average of the other two numbers? A. 10 B. 12 C. 14 D. 16 6- If $$40\%$$ of a number is 4, what is the number? A. 4 B. 8 C. 10 D. 12 7- The average of five numbers is 24. If a sixth number 42 is added, then, which of the following is the new average? A. 25 B. 26 C. 27 D. 42 8- The ratio of boys and girls in a class is 4:7. If there are 44 students in the class, how many more boys should be enrolled to make the ratio 1:1? A. 8 B. 10 C. 12 D. 14 9-What is the slope of the line: $$4x-2y=6$$:_______ 10- A football team had$20,000 to spend on supplies. The team spent $14,000 on new balls. New sports shoes cost$120 each. Which of the following inequalities represent the number of new shoes the team can purchase.

A. 120$$x$$+14,000 $$\leq$$ 20,000

B. 20$$x$$+14,000 $$\geq$$ 20,000

C. 14,000$$x$$+120 $$\leq$$ 20,000

D. 14,000$$x$$+12,0 $$\geq$$ 20,000

$13.99 Satisfied 185 Students ## Answers: 1- 60 Jason needs a score 75 average to pass for five exams. Therefore, the sum of 5 exams must be at lease 5 $$\times$$ 75 = 375 The sum of 4 exams is: 68 + 72 + 85 + 90 = 315 The minimum score Jason can earn on his fifth and final test to pass is: $$375 – 315 = 60$$ 2- B $$Probability = \frac{number \space of \space desired \space outcomes}{number \space of \space total \space outcomes} = \frac{18}{12+18+18+24} = \frac{18}{72} = \frac{1}{4}$$ 3- B The area of the square is 595.36. Therefore, the side of the square is the square root of the area. $$\sqrt{595.36}=24.4$$ Four times the side of the square is the perimeter: $$4 {\times} 24.4 = 97.6$$ 4- A The width of the rectangle is twice its length. Let $$x$$ be the length. Then, width=$$2x$$ Perimeter of the rectangle is $$2 (width + length) = 2(2x+x)=60 {\Rightarrow} 6x=60 {\Rightarrow} x=10$$ The length of the rectangle is 10 meters. 5- D average $$= \frac{sum \space of \space terms}{number \space of \space terms} {\Rightarrow} (average \space of \space 6 \space numbers) \space 12 = \frac{sum \space of \space terms}{6} ⇒sum \space of \space 6 \space numbers\space is$$ $$12 {\times} 6 = 72$$ $$(average \space of \space 4 \space numbers) \space 10 = \frac{sum \space of \space terms}{4}{\Rightarrow} sum \space of \space 4 \space numbers \space is \space 10 {\times} 4 = 40$$ sum of 6 numbers – sum of 4 numbers = sum of 2 numbers $$72 – 40 = 32$$ average of 2 numbers = $$\frac{32}{2} = 16$$ 6- C Let $$x$$ be the number. Write the equation and solve for $$x$$. $$40\% \space of \space x=4{\Rightarrow} 0.40 \space x=4 {\Rightarrow} x=4 {\div}0.40=10$$ 7- C First, find the sum of five numbers. $$average =\frac{ sum \space of \space terms }{ number \space of \space terms } ⇒ 24 = \frac{ sum \space of \space 5 \space numbers }{5}$$ $$⇒ sum \space of \space 5 \space numbers = 24 × 5 = 120$$ The sum of 5 numbers is 120. If a sixth number that is 42 is added to these numbers, then the sum of 6 numbers is 162. 120 + 42 = 162 average $$==\frac{ sum \space of \space terms }{ number \space of \space terms } = \frac{162}{6}=27$$ 8- C The ratio of boys to girls is 4:7. Therefore, there are 4 boys out of 11 students. To find the answer, first, divide the total number of students by 11, then multiply the result by 4. $$44 {\div} 11 = 4 {\Rightarrow} 4 {\times} 4 = 16$$ There are 16 boys and 28 $$(44 – 16)$$ girls. So, 12 more boys should be enrolled to make the ratio 1:1 9- 2 Solve for y. $$4x-2y=6 {\Rightarrow} -2y=6-4x {\Rightarrow} y=2x-3$$ The slope of the line is 2. 10- A Let $$x$$ be the number of new shoes the team can purchase. Therefore, the team can purchase 120 $$x$$. The team had$20,000 and spent $14000. Now the team can spend on new shoes$6000 at most.
Now, write the inequality:
$$120x+14,000 {\leq}20,000$$

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