10 Most Common ATI TEAS 7 Math Questions

C
\(\frac{6^5}{x} = 6^4 = 1,296\)

A
\(P = 2(w +l)\)
\(P = 60\)
\(w= 2l\)
then:
\(60 = 2(2l +l) → 60 = 6l → l = 10\)

B
Volume \(= a × b × c\)
\(2000 = 25 × 10 × c → c = 8\)
Then:
deep \(= 8\)

C
The distance between Chris and Joe is 9 miles. Chris running at 5.5 miles per hour and Joe is running at the speed of 7 miles per hour. Therefore, every hour the distance is 1.5 miles less.
\(9 ÷ 1.5 = 6\)

A
yards \(= 12\) feet
\(\frac{(15 \space feet + 7 \space yards)}{4}=\frac{(15 \space feet + 21 \space yards)}{4}=\frac{(36\space feet )}{4}= 9 \space feet\)

B
\(3\frac{1}{3}-2\frac{5}{6}= 3 + \frac{1}{3}- 2 -\frac{5}{6}=\frac{1}{2}\)

C
Let’s review the choices provided. Put the values of \(x\) and \(y\) in the equation.
A. \((1, 2) ⇒ x = 1 ⇒ y = 2\) This is true!
B. \((−2, −13) ⇒ x = -2 ⇒ y = -13\) This is true!
C. \((3, 18) ⇒ x = 3 ⇒ y = 12\) This is not true!
D. \((2, 7) ⇒ x = 2 ⇒ y = 7\) This is true!

C
If \(a = 3\) then:
\(\frac{8^2}{4} + c ⇒ b = \frac{64}{4} + c = 16 + c \)

C
Circumference \(= 2πr →\) Circumference \(= 2(3.14)(29) = 182.12 \cong 182\)

A
1 foot \(=\) 12 inches
8 feet, 10 inches \(=\) 106 inches
5 feet, 12 inches \(=\) 72 inches
\(106 + 72 =178\)