Full-Length 8th Grade FSA Math Practice Test-Answers and Explanations

Did you take the 8th Grade FSA Math Practice Test? If so, then it’s time to review your results to see where you went wrong and what areas you need to improve.

8th Grade FSA Math Practice Test Answers and Explanations

1- Choice C is correct
Jason ate \(\frac{1}{2}\) of \(8\) parts of his pizza. It means \(4\) parts out of \(8\) parts (\(\frac{1}{2})\) of \(8\) parts is \(x ⇒ x=4\) and left \(4\) parts. Eva ate \(\frac{3}{4}\) of \(8\) parts of her pizza. It means \(6\) parts out of \(8\) parts \(\frac{3}{4}\) of 8 parts is \(x ⇒ x=6\) and left \(2\) parts.
Therefore, they ate \((4 + 6)\) parts out of \((8 + 8)\) parts of their pizza and left \((4 + 2)\) parts out of \((8 + 8)\) parts of their pizza that equals to \(\frac{6}{16}\)
After simplification, the answer is: \(\frac{3}{8}\)

2- The answer is \(5 \frac{7}{10}\) miles.
Robert runs \(3 \frac{1}{10}\) miles on Saturday and \(2×(3 \frac{1}{10} )\) miles on Monday and Wednesday.
Robert wants to run a total of 18 miles this week.
Therefore: \(3 \frac{1}{10}+2×(3 \frac{1}{10})\) should be subtracted from 18:
\(18-(3\frac{1}{10}+2(3 \frac{1}{10}))=15-9 \frac{3}{10}=5 \frac{7}{10}\) miles.

3- Choice A is correct
Let \(x\) be the integer. Then: \(2x+20=68\). Subtract 20 both sides: \(2x=48\). Divide both sides by \(2\) ⇒ \(x=24\)

4- The answer is: –37
Use PEMDAS (order of operation):
\([3×(–21)+(5×2)]–(–25)+[(–3)×6]÷2=[-63+10]+25+[-18]÷2=-53+25-9=-37\)

5- The answer is 768 cm.
Write the proportion and solve for missing side.
\(\frac{Smaller \space triangle \space height}{Smaller \space triangle \space base}
=\frac{Bigger \space triangle \space height}{Bigger \space triangle \space base} ⇒ \frac{100 \space cm}{160 \space cm}=\frac{100+380 \space cm}{x}⇒ x=768 \space cm\)

6- Choice C is correct.
Write the proportion and solve. \(\frac{3 \space ft}{2 \space ft}= \frac{x}{38 \space ft} ⇒ x=57 \space ft\)

7- Choice D is correct.
The distance that Mike runs can be found by the following equation:
\(D_M= 5.5t+7.5\). The distance Julia runs can be found by \(D_J=8t\)
Julia catches Mike if they run the same distance. Therefore:
\(8t=5.5t+7.5⇒2.5t=7.5 ⇒t= \frac{7.5}{2.5}=3\) hours

8- Choice C is correct
x is the number of all sales profit and \(2\%\) of it is:
\(2\%×x=0.02x\). Employer’s revenue: \(0.2x+7,000\)

9- The answer is 60.
Jason needs an \(75\%\) average to pass the exams. Therefore, the sum of 5 exams must be at least \(5×75=375\). The sum of 4 exams is: \(68+72+85+90=315\).
The minimum score Jason can earn on the final test to pass is: \(375–315=60\)

10- Choice C is correct.
We can write: \(\frac{25}{100}=\frac{8}{x}⇒\frac{8×100}{25}=x⇒x=32\)

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11- Choice B is correct.
Let \(x\) be the amount of angle and y be the amount of its supplement. The angle and its supplement are \(180^\circ\) in total \((x+y=180^\circ)\). we have: \(x=\frac{1}{5} y\)
\(x+y=\frac{1}{5} y+y =180^\circ ⇒ y=150^\circ\) and \(x=30^\circ\)

12- Choice D is correct
\(y=-2x+1\) ⇒if \(x=0\) therefore \(y=1\) and if \(x=1\) therefore \(y=-1\). Hence choice D is correct.

13- Choice D is correct
\(\begin{cases}\frac{-x}{2}+\frac{y}{4}=1\\\frac{-5y}{6}+2x=4\end{cases}\)
⇒ Multiply the top equation by 4. Then,
\(\begin{cases}-2x+y=4\\\frac{-5y}{6}+2x=4\end{cases}\)
⇒Add two equations.
\(\frac{1}{6} y=8⇒y=48\) , plug in the value of y into the first equation ⇒\(x=22\)

14- Choice C is correct
\(\begin{cases}x+4y=10\\5x+10y=20\end{cases}\)
⇒Multiply the top equation by -5 then,
\(\begin{cases}-5x-20y=-50\\5x+10y=20\end{cases}\)
⇒Add two equations
\(-10y=-30→y=3\) , plug in the value of \(y\) into the first equation
\(x+4y=10⇒x+4(3)=10⇒x+12=10\)
Subtract 12 from both sides of the equation. Then: \(x+12=10→x=-2\)

15- Choice B is correct.
\(\frac{21+18+16+x}{4} =20⇒\frac{55+x}{4}=20⇒55+x=80⇒x=25\)

16- Choice B is correct.
Solve for \(x\).
\(5≤3x-1<11\)⇒ (add 1 all sides) \(5+1≤3x-1+1<11+1 ⇒ 6≤3x<12\) ⇒ (divide all sides by 3) \(2≤x<4 ⇒x\) is between 2 and 4.

17- Choice D is correct.
Distance between two points is equal: \(\sqrt{(x_1-x_2)^2+(y_1-y_2)^2} =\sqrt{(13-(-2)^2+(-2-6)^2}=\sqrt{15^2+(-8)^2}=\sqrt{225+64}=\sqrt{289}=17\)

18- Choice B is correct
Distance between two points is equal:
\(\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}=\sqrt{(9-4)^2+(7-(-5)^2}=\sqrt{(5)^2+(-12)^2}=\sqrt{169}=13\)

19- Choice D is correct
The slop of line A is: \(m=\frac{y_2-y_1}{x_2-x_1}=\frac{-10-8}{4-(-8)}=-\frac{3}{2}\)
Also \((y-y_1 )=m(x-x_1 )⇒y-8=-\frac{3}{2}(x+8)⇒y=-\frac{3}{2} x-4\)

20- Choice C is correct
The value of \(y\) in the \(x\)-intercept of a line is zero. Then:
\(y=0→10x-4(0)=5→10x=5→x=\frac{1}{2}\). Then, \(x\)-intercept of the line is \(\frac{1}{2}\)

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21- Choice C is correct
The total amount of money Giselle made as a carpenter can be modeled by \(20x\), and the total amount of money she made as a blacksmith can be modeled by \(25y\). Since these together add up to $690, we get the following equation:
\(20x+25y=690\).
We are also given that last week, Giselle worked as a carpenter and a blacksmith for a total of 30 hours. This can be expressed as:
\(x+y=30⇒y=30-x\)
Therefor \(20x+25(30-x)=690⇒x=12\) and \(y=18\)

22- Choice D is correct
\(\begin{cases}3x+y=8\\-5x-2y=0\end{cases}\)
Multiply the top equation by 2 then,
\(\begin{cases}6x+2y=16\\-5x-2y=0\end{cases}\)
⇒ Add two equations
\(x=16\) , plug in the value of \(y\) into the first equation
\(3x+y=8→3(16)+y=8→y=-40\)

23- Choice D is correct
Let \(x=\) the total miles of the ride.
Therefore, \(x-1=\) the additional miles of the ride. The correct equation takes $1.25 and adds it to $1.15 times the number of additional miles, \(x-1\). Translating, this becomes: \(y\)(the total cost)\(=1.25+1.15(x-1)\), which is the same equation as \(y=1.15(x-1)+1.25\).

24- Choice D is correct.
Write as two points in terms of: (number of people, cost in$) (15,120) and (25,200). Find the equation of the line using: m\(=\frac{y_2–y_1}{x_2–x_1}\) and \(y=mx+b\)
Equation: \(y=8x\) plug in \(x=40\), \(y=8(40)=320\). A party of 40 people will cost $320.00.

25- Choice A is correct
\(C=250+150h\). Assuming the initial meeting counts for the 1st hour, you would plug in \(h=25\) for a total cost of $4000.00.

26- Choice D is correct
Let the number be \(x\). Then the other number\(=x+8\). Sum of two numbers \(=30\). According to question, \(x+x+8=30 ⇒2x+8=30⇒ 2x=22⇒ x=11\). Therefore, \(x+8=11+8=19\)

27- Choice C is correct.
\(0.0000005823=5.823 × 10^{-7}\)

28- Choice B is correct.
\(28,000,000,000=2.8×10^{10}\)

29- Choice B is correct.
The area of greater circle is: \(A_g=πr^2=π .(45)^2=6361.7 \space mm^2\)
The area of smaller circle is: \(A_s=πr^2=π .(33)^2=3421.2 \space mm^2\)
Then area of colored part is \(A_c=A_g-A_s=6361.7-3421.2=2940.5 \space mm^2\)

30- Choice C is correct.
When a point is reflected over y axes, the \((x)\) coordinate of that point changes to \((-x)\), while its y coordinate remains the same.

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