FREE 7th Grade OST Math Practice Test

For Sum 6: (1 & 5) and (5 & 1), (2 & 4) and (4 & 2), (3 & 3), so we have 5 options.
For sum 9: (3 & 6) and (6 & 3), (4 & 5) and (5 & 4), we have 4 options.
To get a sum of 6 or 9 for two dice: \(5+4=9\)
Since we have \(6 × 6 = 36\) total options, the probability of getting a sum of 6 and 9 is 9 out of 36 or \(\frac{1}{4}\).

The equation of a line in slope intercept form is: \(y = mx + b\)
Solve for \(y\).
\(4x-2y=12 ⇒ -2y=12-4x ⇒ y=(12-4x)÷(-2) ⇒ y=2x-6\)
The slope of this line is 2.
The product of the slopes of two perpendicular lines is\( -1\).
Therefore, the slope of a line that is perpendicular to this line is:
\(m_1 × m_2 = -1 ⇒ 2 × (m_2) = -1 ⇒ (m_2) = -\frac{1}{2}\)

For each option, choose a point in the solution part and check it on both inequalities.
A. Point \((–4, –4)\) is in the solution section. Let’s check the point in both inequalities.
\(–4 ≤ – 4 + 4, \space It \space works\)
\(2 (–4) + (–4) ≤ –4 ⇒ – 12 ≤ – 4\) it works (this point works in both)
B. Let’s choose this point \((0, 0)\)
\(0 ≤ 0 + 4, \space It \space works\)
\(2 (0) + (0) ≤ –4, \space \space That’s \space not \space true!\)
C. Let’s choose this point \((–5, 0)\)
\(0 ≤ –5 + 4, \space That’s \space not \space true!\)
D. Let’s choose this point \((0, 5)\)
\(5 ≤ 0 + 4, \space That’s \space not \space true!\)

Let \(x\) be the number of new shoes the team can purchase. Therefore, the team can purchase 120 \(x\).
The team had $20,000 and spent $14000. Now the team can spend on new shoes $6000 at most.
Now, write the inequality:
\(120x+14.000 ≤20.000\)

Use a simple interest formula:
I=prt
(I = interest, p = principal, r = rate, t = time)
\(I=(8000)(0.045)(5)=1800\)

Let \(x\) be the number of years. Therefore, $2,000 per year equals 2000\(x\).
starting from $24,000 annual salary means you should add that amount to 2000\(x\).
Income more than that is:
\(I > 2000x + 24000\)