Top 10 6th Grade OST Math Practice Questions

Have your students studied the 6th Grade OST Math test content well? If so, now is the time to practice! Using 10 of the best 6th Grade OST Math practice questions prepared in this article, your students can increase their readiness to take the 6th Grade OST Math test and get the excellent score they want. These questions have been fully updated to reflect the latest 2022 6th Grade OST Math guidelines. Answers and full explanations are provided at the end of the post.

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6th Grade OST Math Practice Questions

1- Which expression is equivalent to \(5(12x-16)\)?

A. \(-20\)

B. \(-20x\)

C. \(60x – 16\)

D. \(60x – 80\)

2- To produce a special concrete, for every 13 kg of cement, 3 liters of water is required. Which of the following ratios is the same as the ratio of cement to liters of water?

A. 91: 21

B. 14: 4

C. 39: 6

D. 9: 39

3- What is the value of \(x\) in the following equation: \(-60=115-x\)

A. 175

B. \(-175\)

C. 55

D. \(-55\)

4- Which of the following graphs represents the following inequality?
\(-8≤5x-8≤2\)

A.

B.

C.

D.

5- The ratio of boys to girls in a school is 4:5. If there are 765 students in the school, how many boys are in the school?

A. 612

B. 510

C. 425

D. 340

6- Martin earns $20 an hour. Which of the following inequalities represents the amount of time Martin needs to work per day to earn at least $100 per day?

A. \(20t≥100\)

B. \(20t≤100\)

C. \(20+t≥100\)

D. \(20+t≤100\)

7- \((55+5)÷12\) is equivalent to …

A. \(60÷3.4\)

B. \( \frac{55}{12}+5\)

C. \((2×2×3×5)÷(3×4)\)

D. \( (2×2×3×5)÷3+4\)

8- What is the value of the expression \(6(2x-3y)+(3-2x)^2\), when \(x=2 \) and \(y=-1\)?

A. \(-23\)

B. 41

C. 43

D. 49

9- Round \(\frac{215}{7}\) to the nearest tenth.

A. 31

B. 30.8

C. 30.7

D. 30

10- A chemical solution contains \(6\%\) alcohol. If there is 45 ml of alcohol, what is the volume of the solution?

A. 270 ml

B. 420 ml

C. 750 ml

D. 1,200 ml

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Answers:

2- A
\(91 : 21 = 13 : 3\)
\(13×7=91\)
And \( 3×7=21\)

3- A
\(-60 = 115 – x\)
First, subtract 115 from both sides of the equation. Then:
\(-60 – 115=115 – 115- x→-175 = – x\)
Multiply both sides by \((-1)\):
\(→x = 175\)

4- B
\(-8≤5x-8<2 →\) (add 8 all sides)\(-8+8≤5x-8+8<2+8 →0≤5x<10→\) (divide all sides by 5) \(0≤x<2\)

5- D
The ratio of boy to girls is 4:5. Therefore, there are 4 boys out of 9 students. To find the answer, first, divide the total number of students by 9, then multiply the result by 4.
\(765 ÷ 9 = 85 ⇒ 85 × 4 = 340\)

6- A
For one hour he earns $20, then for t hours he earns $20t. If he wants to earn at least $100, therefore, the number of working hours multiplied by 20 must be equal to 100 or more than 100.
\(20t≥100\)

7- C
\((55+5)÷(12)=(60)÷(12)\)
The prime factorization of 60 is: \(2×2×3×5 \)
The prime factorization of 12 is: \( 3×4 \)
Therefore: \((60)÷(12)=(2×2×3×5)÷(3×4)\)

8- C

Plug in the value of \(x\) and \(y\) and use the order of operations rule.
\(x=2\) and \(y=-1\)
\(6(2x-3y)+(3-2x)^2=6(2(2)-3(-1))+(3-2(2))^2=6(4+3)+(-1)^2 = 42+1=43\)

9- C
\(\frac{215}{7} ≅ 30.71 ≅ 30.7\)

10- C
\(6\%\) of the volume of the solution is alcohol. Let \(x\) be the volume of the solution.
Then: \(6\% \space of \space x = 45 \space ml ⇒ 0.06 x = 45 ⇒ x = 45 ÷ 0.06 = 750\)

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