10 Most Common 6th Grade OST Math Questions
One of the methods that calms students and boosts their self-confidence is taking the 6th Grade OST sample practice test. As students become more familiar with the sample of 6th Grade OST exam questions, the level of difficulty and variety of questions becomes clear to them. Therefore, they will no longer have to worry about not being familiar with the type of questions and topics of the 6th Grade OST exam.
In this article, we have prepared 10 common math questions of the 6th Grade OST exam with their solutions in order to make your students more familiar with the type and format of test questions.
Make sure to follow some of the related links at the bottom of this post to get a better idea of what kind of mathematics questions your students need to practice.
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10 Sample 6th Grade OST Math Practice Questions
What is the equation of a line that passes through points \((0, 4)\) and \((2, 8)\)?
\(y = x\)
\(y = x + 4\)
\(y = 2x + 4\)
\(y = 2x – 4\)
Show answer and explanation
C
The slope of the line is:
\(\frac{y_2-y_1}{x_2-x_1 }= \frac{8 – 4}{2 – 0}=\frac{4}{2}=2\)
The equation of a line can be written as:
\( y-y_0=m(x – x_0 )→y-4 = 2(x – 0)→y-4 = 2x→y = 2x + 4\)
What is the volume of a box with the following dimensions?
Height \(= 6\) cm , Width \(= 7\) cm, Length \(= 9\) cm
\(63 \space cm^3\)
\(126\space cm^3\)
\(189\space cm^3\)
\(378\space cm^3\)
Show answer and explanation
D
Volume of a \(box = length × width × height = 6 × 7 × 9 = 378\)
Anita’s trick–or–treat bag contains 14 pieces of chocolate, 15 suckers, 16 pieces of gum, and 20 pieces of licorice. If she randomly pulls a piece of candy from her bag, what is the probability of her pulling out a piece of sucker?
\(\frac{1}{13}\)
\(\frac{3}{13}\)
\(\frac{14}{65}\)
\(\frac{16}{65}\)
Show answer and explanation
B
\(Probability = \frac{number \space of \space desired \space outcomes}{number \space of \space total \space outcomes}=\frac{15}{14+15+16+20}= \frac{15}{65}=\frac{3}{13}\)
In the following rectangle, which statement is false?
AD is parallel to BC
The measure of the sum of all the angles equals \(360^\circ\).
Length of AB equal to length DC.
AB is perpendicular to AC.
Show answer and explanation
D
In any rectangle, sides are not perpendicular to diagonals.
The area of a rectangular yard is 90 square meters. What is its width if its length is 15 meters?
10 meters
8 meters
6 meters
4 meters
Show answer and explanation
C
Let y be the width of the rectangle. Then; \(15×y=90→y=\frac{90}{15}=6\)
Which statement about 4 multiplied by \(\frac{3}{5}\) must be true?
The product is between 1 and 2
The product is greater than 3
The product is equal to \(\frac{75}{31}\)
The product is between 2 and 2.5
Show answer and explanation
D
\( 4×\frac{3}{5}=\frac{12}{5}=2.4 \)
\( 2.4>2\)
\( 2.4<3\)
\( \frac{75}{31}=2.419≠2.4\)
\(2<2.4<2.5 \) This is the answer!
Which of the following lists shows the fractions in order from least to greatest?
\(\frac{3}{4}, \frac{2}{7}, \frac{3}{8} , \frac{5}{11}\)
\(\frac{3}{8}, \frac{2}{7}, \frac{3}{4}, \frac{5}{11}\)
\(\frac{2}{7}, \frac{5}{11}, \frac{3}{8}, \frac{3}{4}\)
\(\frac{2}{7}, \frac{3}{8}, \frac{5}{11}, \frac{3}{4}\)
\(\frac{3}{8}, \frac{2}{7}, \frac{5}{11}, \frac{3}{4}\)
Show answer and explanation
C
Let’s compare each fraction:
\(\frac{2}{7}< \frac{3}{8}< \frac{5}{11} < \frac{3}{4}\)
Only choice C provides the right order.
A car costing $300 is discounted \(10\%\). Which of the following expressions can be used to find the selling price of the car?
\((300)(0.4)\)
\(300-(300×0.1)\)
\((300)(0.1)\)
\( 300-(300×0.9)\)
Show answer and explanation
B
To find the discount, multiply the number (\(100\%\)- rate of discount)
Therefore; \(300(100\%-10\%)=300(1-0.1)=300-(300×0.1)\)
What is the missing price factor of the number 420?
\(420=2^2×3^1×…\)
\(2^2×3^1×5^1×7^1\)
\(2^2×3^1×7^1×9^1\)
\(1^2×2^3×2^1×3^1\)
\(3^2×5^1×7^1×9^1\)
Show answer and explanation
A
\(420=2^2×3^1×5^1×7^1\)
If the area of the following trapezoid is equal to A, which equation represents \(x\)?
\(x = \frac{13}{A}\)
\(x = \frac{A}{13}\)
\( x=A+13\)
\( x=A-13\)
Show answer and explanation
B
The area of the trapezoid is: area= \(\frac{(base 1+base 2)}{2}×height= (\frac{10 + 16}{2})x = A\)
\( →13x = A→x = \frac{A}{13}\)
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