One of the surest ways to succeed in the 6th Grade OST Math test is to practice hard, and this is what we intend to provide for your 6th Grade students in this article. In fact, our professional team have been working in the field of providing mathematics practice tests to students for many years. And now in this article, we are going to share our experiences with you by providing the best 6th Grade OST Math test sample practice questions. These questions are examples designed for your students to gain the knowledge they need to prepare for the 6th Grade OST Math test.

Start preparing your student for the 2021 OST Math test with our free sample practice questions. Also, make sure to follow some of the related links at the bottom of this post to get a better idea of what kind of mathematics questions students need to practice.

## The Absolute Best Book** to Ace 6th Grade OST Math** Test

## 10 Sample **6th Grade OST** Math Practice Questions

1- If the area of the following trapezoid is equal to A, which equation represent \(x\)?

\( \img {https://appmanager.effortlessmath.com/public/images/questions/131313444444444444444444444444444.JPG

} \)

A. \(x = \frac{13}{A}\)

B. \(x = \frac{A}{13}\)

C. \(x=A+13\)

D. \(x=A-13\)

2- By what factor did the number below change from first to fourth number?

\(8, 104, 1352, 17576\)

A. 13

B. 96

C. 1456

D. 17568

3- 170 is equal to …

A. \(-20-(3×10)+(6×40)\)

B. \(((\frac{15}{8})×72 )+ (\frac{125}{5}) \)

C. \(((\frac{30}{4} + \frac{15}{2})×8) – \frac{11}{2} + \frac{222}{4}\)

D. \(\frac{481}{6} + \frac{121}{3}+50\)

4- The distance between two cities is 3,768 feet. What is the distance of the two cities in yards?

A. 1,256 yd

B. 11,304 yd

C. 45,216 yd

D. 3,768 yd

5- Mr. Jones saves $3,400 out of his monthly family income of $74,800. What fractional part of his income does Mr. Jones save?

A. \(\frac{1}{22}\)

B. \(\frac{1}{11}\)

C. \(\frac{3}{25}\)

D. \(\frac{2}{15}\)

6- What is the lowest common multiple of 12 and 20?

A. 60

B. 40

C. 20

D. 12

7- Based on the table below, which expression represents any value of f in term of its corresponding value of \(x\)?

\( \img {https://appmanager.effortlessmath.com/public/images/questions/28282828288888888888888888888888888888888.JPG

} \)

A. \(f=2x-\frac{3}{10}\)

B. \(f=x+\frac{3}{10}\)

C. \(f=2x+2 \frac{2}{5}\)

D. \(2x+\frac{3}{10}\)

8- Solve: 96 kg = … ?

A. 96 mg

B. 9,600 mg

C. 960,000 mg

D. 96,000,000 mg

9- Calculate the approximate area of the following circle? (the diameter is 25)

\( \img {https://appmanager.effortlessmath.com/public/images/questions/3030303000000000000000000000000000.JPG

} \)

A. 78

B. 491

C. 157

D. 1963

10- The following graph shows the mark of six students in mathematics. What is the mean (average) of the marks?

\( \img {https://appmanager.effortlessmath.com/public/images/questions/313131313131111111111111111111111111111111111111.JPG

} \)

A. 13

B. 13.5

C. 14

D. 1.5

## Best **6th Grade OST** Math Exercise Resource for 2021

## Answers:

1- **B**

The area of the trapezoid is: area\(= \frac{(base 1+base 2)}{2}×\)height\(= (\frac{10 + 16}{2})x = A\)

\( →13x = A→x = \frac{A}{13}\)

2- **A**

\(\frac{104}{8}=13, \frac{1352}{104}=13, \frac{17576}{1352}=13\)

Therefore, the factor is 13

3-** C**

Simplify each option provided.

A. \(-20-(3×10)+(6×40)=-20-30+240=190\)

B. \((\frac{15}{8})×72 + (\frac{125}{5}) =135+25=160\)

C. \(((\frac{30}{4} + \frac{15}{2})×8) – \frac{11}{2} + \frac{222}{4} = ((\frac{30 + 30}{4})×8)- \frac{11}{2}+ \frac{111}{2}=(\frac{60}{4})×8) + \frac{100}{2}= 120 + 50 = 170\)

this is the answer

D. \(\frac{481}{6} + \frac{121}{3}+50= \frac{481+242}{6}+50=120.5+50=170.5\)

4- **A**1 yard \(= 3\) feet

Therefore, \(3,768 ft × \frac{1 \space yd }{3 \space ft}=1,256 \space yd\)

5- **A**

3,400 out of 74,800 equals to \(\frac{3,400}{74,800}=\frac{17}{374}=\frac{1}{22}\)

6- **A**

Prime factorizing of \(20=2×2×5\)

Prime factorizing of \(12=2×2×3\)

LCM\(=2×2×3×5=60\)

7- **C**

Plug in the value of \(x\) into the function f. First, plug in 3.1 for\( x\).

A. \(f=2x-\frac{3}{10}=2(3.1)-\frac{3}{10}=5.9≠8.6\)

B. \(f=x+\frac{3}{10}=3.1+\frac{3}{10}=3.4≠10.8\)

C. \(f=2x+2 \frac{2}{5}=2(3.1)+2 \frac{2}{5}=6.2+2.4=8.6\)

This is correct!

Plug in other values of \(x. (x=4.2)\)

\(f=2x+2\frac{2}{5} =2(4.2)+2.4=10.8 \)

This one is also correct.

\(x=5.9\)

\(f=2x+2 \frac{2}{5}=2(5.9)+2.4=14.2 \)

This one works too!

D. \(2x+\frac{3}{10}=2(3.1)+\frac{3}{10}=6.5≠8.6\)

8- **D**

1 kg\(= 1000\) g and 1 g \(= 1000\) mg

\(96\) kg\(= 96 × 1000\) g \(= 96 × 1000 × 1000 = 96,000,000\) mg

9- **B**

The diameter of a circle is twice the radius. Radius of the circle is \(\frac{25}{2}\).

Area of a circle = \(πr^2=π(\frac{25}{2})^2=156.25π=156.25×3.14=490.625≅491\)

10- **B**

Average (mean) \(=\frac{sum \space of \space terms}{number \space of \space terms}= \frac{10+11+15+14+15+17+12.5}{7}=13.5\)

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