ACCUPLACER Math Practice Test Questions
B. \(\frac{4}{5}\)
C. \(\frac{4}{3}\)
D. \(\frac{3}{4}\)
7- Find the slope-intercept form of the graph \(6x – 7y = – 12\)
A. \(y = – \frac{7}{6} x – \frac{12}{7}\)
B. \(y = – \frac{6}{7} x + 12\)
C. \(y = \frac{6}{7} x + \frac{12}{7}\)
D. \(y = \frac{7}{6}x – 12\)
8- Ella (E) is 4 years older than her friend Ava (A) who is 3 years younger than her sister Sofia (S). If E, A, and S denote their ages, which one of the following represents the given information?
A. \(E=A+4\)
\(S=A-3\)
B. \(E=A+4\)
\(A=S+3\)
C. \(A=E+4\)
\(S=A-3\)
D. \(E=A+4\)
\(A=S-3\)
9- Which of the following point is the solution of the system of equations?
\(5x + y = 9\)
\(10x-7y= -18\)
A. \((2, 4)\)
B. \((2, 2)\)
C. \((1, 4)\)
D. \((0, 4)\)
10- Find the Center and Radius of the graph \((x – 3)^2 + (y + 6)^2 = 12\)
A. \((3, 6), \sqrt{3}\)
B. \((3, –6), 2\sqrt{3}\)
C. \((–3, 6), 2\sqrt{3}\)
D. \((3, –6), \sqrt{3}\)
Best ACCUPLACER Math Prep Resource for 2026
Answers:
1- D
\((g – f)(x) = g(x) – f(x) = (– x^2 – 1 – 2x) – (5 + x)\)
\(– x^2 – 1 – 2x – 5 – x = – x^2 – 3x – 6\)
2- B
\(\frac{|3+x|}{7} ≤5⇒|3+x|≤35⇒-35≤3+x≤35⇒-35-3≤x≤35-3⇒
-38≤x≤32 \)
3- D
\((– \frac{π}{6}) = -\frac{\sqrt 3}{3}\)
4- A
\(\frac{\sqrt{32a^5 b^3}}{\sqrt{2ab^2}}=\frac{4a^2 b\sqrt{2ab}}{b\sqrt{2a}}= 4a^2 \sqrt b\)
5- D
\( c(3)=(3)^2+10(3)+30=9+30+30=69\)
\(4×3=12⇒12-69=-57⇒57,000 \space\) loss
6- B
\(sinB=\frac{the \space length \space of \space the \space side \space that \space is \space opposite \space that \space angle}{the \space length \space of \space the \space longest \space side \space of \space the \space triangle} =\frac{4}{5}\)
7- C
\(-7y=-6x-12⇒y=\frac{-6}{-7}x-\frac{12}{-7}⇒y=\frac{6}{7}x+\frac{12}{7}\)
8- D
\(E = 4 + A\)
\(A = S – 3\)
9- C
\(5x + y = 9\)
\(10x-7y= -18\)
⇒ Multiplication \((–2)\) in first equation ⇒
\(-10x- 2y = -18 \)
\(10x-7y= -18\)
Add two equations together \(⇒ –9y = –36 ⇒ y = 4\) then: x = 1\)
10- B
\((x – h)^2 + (y – k)^2 = r^2 \) ⇒ center: \((h,k)\) and radius: \(r\)
\((x – 3)^2 + (y + 6)^2 = 12 \)⇒ center: \((3,-6)\) and radius: \(2\sqrt {3}\)
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