This is a great math challenge *that hones students’* logic and creative thinking skills the fun way.

## Challenge:

\(4^{20}+4^{20}+4^{20}+4^{20} =\) ?

**A-** \(4^{120}\)

**B-** \(16^{30}\)

**C-** \(4^{30}\)

**D-** \(2^{40}\)

**E-** \(2^{42}\)

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The correct answer is E.

Factorize \(4^{20}\):

\(4^{20}+4^{20}+4^{20}+4^{20} = 4^{20 } (1 + 1 + 1 + 1) = 4^{20 } (4) = 4^{21}\)

\(4^{21} = (2^2)^{21} = 2^{42}\)