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This is a great math challenge that hones students’ logic and creative thinking skills the fun way.
\(4^{20}+4^{20}+4^{20}+4^{20} =\) ?
A- \(4^{120}\)
B- \(16^{30}\)
C- \(4^{30}\)
D- \(2^{40}\)
E- \(2^{42}\)
The correct answer is E.
Factorize \(4^{20}\):
\(4^{20}+4^{20}+4^{20}+4^{20} = 4^{20 } (1 + 1 + 1 + 1) = 4^{20 } (4) = 4^{21}\)
\(4^{21} = (2^2)^{21} = 2^{42}\)
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