# Intelligent Math Puzzle – Challenge 88

A great mathematical and logic puzzle designed for those interested in school-level Maths. The answer is also given.

## Challenge:

In the figure above, A, B, C, and D represent different digits. What is the value of A × B + C + D?

A- 6

B- 12

C- 34

D- 40

E- 45

$11.99 Satisfied 123 Students The correct answer is A. A, B, C, and D represent different digits. The sum of three 3-digit numbers is a 4-digit number with 1 or 2 in the thousands place. Therefore, D = 1 or 2. And A is 3 or greater than 3. Why? A + A + A = 12 or 12+1, Why? Since, A is a digit, then 3A cannot be 13. 3A = 12 ⇒ A = 4 We also know that C + C + C = C or C + 10 C = 0 or 3C = C + 10 → 2C = 10 → C = 5 Therefore, C is 0 or 5. Let’s assume D = 1. Then: If C = 0 → B + B + B = 1 or B + B + B = 1 + 10 3B = 1 (This is not correct) or 3B = 1 + 10 (This is not correct either). If C = 5 → B + B + B + 1 = D → D = 1 → 3B = 1 – 1= 0 or B + B + B + 1 = D + 10 → 3B + 1 = 1 + 10 → B $$= \frac{10}{3}$$ B is an integer and cannot be $$\frac{10}{3}$$. In this situation, the only value of B is 0. If A = 4, B = 0 and C = 5, then 405 + 405 + 405 = 1215 Bingo! You can check out other values for A, B, C, and D. But, only the above values work. A × B + C + D = 4 × 0 + 5 + 1 = 6 ### More math articles ### What people say about "Intelligent Math Puzzle - Challenge 88"? No one replied yet. X 30% OFF Limited time only! Save Over 30% SAVE$5

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