Top 10 5th Grade PSSA Math Practice Questions
Top 10 5th Grade PSSA Math Practice Questions is a multiple-choice math challenge from Effortless Math. Read the problem, choose from the answer options below, then open the solution to see the full step-by-step working and check your reasoning against it.
A. (8 π)
B. (16 π)
C. (32 π)
D. (64 π)
8- A rope weighs 800 grams per meter of length. What is the weight in kilograms of 12.2 meters of this rope? (1 kilograms = 1000 grams)
A. 0.0976
B. 0.976
C. 9.76
D. 9760
9- Solve.
(frac{1}{2} + frac{4}{5} – frac{3}{10} =?)
A. (frac{9}{10})
B. (frac{2}{10})
C. 1
D. 2
10- How many (frac{1}{4}) cup servings are in a package of cheese that contains (6 frac{1}{2}) cups altogether?_________
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Answers:
1- A
There are 65 cards in the bag and 13 of them are white. Then, 13 out of 65 cards are white. You can write this as: (frac{13}{65}).
To simplify this fraction, divide both numerator and denominator by 13. Then:
(frac{13}{65}=frac{1}{5})
2- B
(frac{3}{11}) means 3 is divided by 11. The fraction line simply means division or (÷). Therefore, we can write (frac{3}{11}) as (3 ÷ 11).
3- A
Plugin 20 for A in the equations. Only option A works.
(A+20=40)
(20+20=40)
4- D
50 miles: 1 hour
425 miles: (425 ÷ 50 = 8.5) hours
5- C
Use percent formula:
(part =frac{percent}{100}× whole)
(50=frac{percent}{100}× 40⇒ 50 = frac{percent ×40}{100}⇒ 50 = frac{percent ×4}{10})
multiply both sides by 10.
500 = percent (×4), divide both sides by 4.
125 = percent
6- 104
First, find the missing side of the trapezoid. The perimeter of the trapezoid below is 52. Therefore, the missing side of the trapezoid (its height) is: (52-12-18-14=52-44=8)
Area of a trapezoid: (A = frac{1}{2} h (b_{1} + b_{2}) = frac{1}{2} (8) (12 + 14) = 104)
7- B
Use area and circumference of a circle formula.
Area of a circle = (πr^2 ⇒ 64π = πr^2 ⇒ r= 8)
Circumference of a circle = (2πr ⇒ C = 2×8×π ⇒ C =16π)
8- C
1 meter of the rope = 800 grams 12.2 meter of the rope = (12.2 × 800 =9,760 )grams = 9.76 kilograms
9- C
(frac{1}{2} + frac{4}{5}, frac{3}{10} = frac{(5×1)+(2×4)-(1×3)}{10} =frac{10}{10}=1)
10- 26
To solve this problem, divide (6frac{1}{2}) by (frac{1}{4}).
(6frac{1}{2}÷frac{1}{4}=frac{13}{2}÷frac{1}{4}=frac{13}{2}×frac{4}{1}=26)
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