How to Solve Compound Inequalities: And, Or and Graphing

To solve compound inequalities, solve each inequality and combine the results. “And” keeps values that satisfy both conditions; “or” keeps values that satisfy at least one. Graph the final set with open circles for < or > and closed circles for ≤ or ≥.

How to Solve Compound Inequalities: And, Or and Graphing

And: find the overlap

Solve 4 < x + 2 < 8. This is shorthand for two conditions joined by “and”: 4 < x + 2 and x + 2 < 8.

Subtract 2 from all three parts: 2 < x < 6.

On a number line, put open circles at 2 and 6 and shade between them. The interval is (2, 6). For example, 4 works in both conditions. The endpoints 2 and 6 do not, because the inequalities are strict.

For a double inequality, perform the same operation on all three parts. For separate “and” conditions, solve them separately, then keep only their shared values.

Or: combine the solutions

Solve 2x + 1 ≤ -3 or 3x – 2 > 10.

  1. From 2x + 1 ≤ -3, subtract 1 and divide by 2: x ≤ -2.
  2. From 3x – 2 > 10, add 2 and divide by 3: x > 4.
  3. Keep either region: x ≤ -2 or x > 4.

Graph a closed circle at -2 with shading to the left, and an open circle at 4 with shading to the right. The interval notation is (-∞, -2] ∪ (4, ∞). The union symbol ∪ means combine the sets. Always use parentheses with infinity.

When the “or” regions overlap

The original example 4 < x + 2 < 8 or x – 5 > 0 gives 2 < x < 6 or x > 5. These regions overlap between 5 and 6, so together they cover every value greater than 2. The simplest answer is x > 2, or (2, ∞). An “or” answer does not always have two separate pieces.

Dividing by a negative: reverse both signs

Solve -6 < -2x ≤ 8. Divide every part by -2 and reverse each comparison:

3 > x ≥ -4, which is clearer in increasing order as -4 ≤ x < 3.

The graph has a closed circle at -4, an open circle at 3, and shading between them. The interval is [-4, 3). Adding or subtracting a number does not reverse the comparison signs.

No solution or all real numbers

  • x > 5 and x < 1: there is no overlap, so there is no solution. You can write ∅.
  • x > 1 or x < 5: the regions together include every real number, so the solution is all real numbers, written (-∞, ∞).

Check more than one value when comparing solution sets. Test an interior value, each endpoint, and a value outside the shaded region. One working value confirms that value is a solution; it does not prove the entire set is correct.

Worksheet and practice

For printable work, choose Compound Inequalities in the free Algebra 1 worksheet collection. The linked topic PDF includes solving practice and visual number-line questions. Use this lesson to check whether each final graph should show an overlap or a union.

Review solving linear inequalities if you need the individual steps, or use the Algebra 1 learning hub for related skill review.

Try two compound inequalities

1. Solve -1 ≤ 2x + 3 < 9.
2. Solve x – 4 < -2 or x + 1 ≥ 6.

Show the solutions

1. Subtract 3, then divide by 2: -2 ≤ x < 3, or [-2, 3).
2. Solve each part: x < 2 or x ≥ 5, or (-∞, 2) ∪ [5, ∞).

The existing pop-up below reviews single-inequality skills used in these compound problems.

Tutor-style math help

Solve Compound Inequalities: what to notice and how to work it

Inequalities skill
Inequalities describe a set of possible values. Solve the boundary like an equation, then decide which side of the boundary makes the statement true.

What to notice first

Watch the comparison sign from the first line to the last. Multiplying or dividing by a negative reverses the direction.

Common student mistake

Do not forget open and closed endpoints. Strict signs use open circles; signs with equals use closed circles.

Key formulas and cues

\(a<b\)
\(a\le b\)
\(\text{multiply/divide by a negative} \Rightarrow \text{reverse the sign}\)
\(|x-a|<b \Rightarrow a-b<x<a+b\)
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A reliable path

  1. Solve the boundaryTemporarily treat the inequality like an equation.
  2. Choose the sideUse the sign or test a number if the direction is not obvious.
  3. Graph the solutionUse the correct endpoint and shade the values that work.

Worked examples

Flip the sign

Example: \(-3x>12\)
  1. Divide both sides by -3.
  2. Reverse the inequality sign.
  3. Simplify 12 divided by -3.
Answer: \(x<-4\)

Keep the sign

Example: \(x+5\le9\)
  1. Subtract 5 from both sides.
  2. No negative multiplication or division happened.
  3. Keep the sign direction.
Answer: \(x\le4\)
Try one before moving on
Try: Solve \(-2x\le10\).
Answer: \(x\ge-5\). Divide by -2 and flip the sign.
Next step: do the matching worksheet or quiz while the method is still fresh, then come back and explain the first step in your own words.

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