Adding and Subtracting Matrices: Examples and Free Practice
To add or subtract matrices, combine entries in the same row and column. Both matrices must have exactly the same dimensions. Use the worked examples below, try the eight free practice problems, and check your answers.
Add and Subtract Matrices: what to notice and how to work it
To add or subtract matrices, first check that they have the same number of rows and columns. Then combine entries in matching positions. The answer keeps the same dimensions.
Add matching entries
For row matrices [1, 4] + [2, 3], calculate 1 + 2 and 4 + 3. The result is [3, 7].
Keep subtraction in order
For [1, 4] − [2, 3], calculate 1 − 2 and 4 − 3. The result is [−1, 1]. Reversing the matrices changes the answer.
Check before you calculate
- Count rows and columns in both matrices.
- If their dimensions differ, you cannot add or subtract them.
- Work position by position. When subtracting a negative entry, use a plus sign: 2 − (−2) = 4.
- Check that your answer has the same dimensions as the starting matrices.
Try one before moving on
Subtract [5, −2] from [−1, 2].
Answer: [−6, 4], because −1 − 5 = −6 and 2 − (−2) = 4.
For another explanation of the dimension rule, see OpenStax: Matrices and Matrix Operations.
Add and Subtract Matrices: pop-up practice
Worked examples
Adding and Subtracting Matrices, Example 1:
\(\begin{bmatrix} 2 & -5 & -3 \end{bmatrix}+ \begin{bmatrix}1 & -2 & -3 \end{bmatrix}\)
Solution:
Add the elements in the matching positions: \(\begin{bmatrix} 2+1 & -5+(-2) & -3+(-3) \end{bmatrix}= \begin{bmatrix}3 & -7 & -6 \end{bmatrix}\)
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Adding and Subtracting Matrices, Example 2:
\(\begin{bmatrix}3 & 6 \\-1 & -3 \\-5 & -1\end{bmatrix}+ \begin{bmatrix}0 & -1 \\6 & 0 \\2 & 3\end{bmatrix} \)
Solution:
Add the elements in the matching positions: \(\begin{bmatrix}3+0 & 6+(-1) \\-1+6 & -3+0 \\-5+2 & -1+3\end{bmatrix} = \begin{bmatrix}3 & 5 \\5 & -3 \\-3 & 2\end{bmatrix} \)
Adding and Subtracting Matrices, Example 3:
\(\begin{bmatrix}2 & -1 \\0 & 1 \end{bmatrix}+\begin{bmatrix}3 & 1 \\5 & -2 \end{bmatrix}\)
Solution:
Add the elements in the matching positions: \(\begin{bmatrix}2+3 & -1+1 \\0+5 & 1+(-2) \end{bmatrix}=\begin{bmatrix}5 & 0 \\5 & -1 \end{bmatrix}\)
Adding and Subtracting Matrices, Example 4:
\(\begin{bmatrix}-1 & 2 \\3 & 4 \\0 & -2\end{bmatrix}- \begin{bmatrix}5 & -2 \\6 & 1 \\-3 & 4\end{bmatrix} \)
Solution:
Subtract the elements in the matching positions: \(\begin{bmatrix}-1-5 & 2-(-2) \\3-6 & 4-1 \\0-(-3) & -2-4\end{bmatrix}= \begin{bmatrix}-6 & 4 \\-3 & 3 \\3 & -6\end{bmatrix}\)
Eight free practice problems
Work these on paper, then compare each entry with the answers below. The existing book-preview button is a separate resource.
- \(\color{blue}{\begin{bmatrix}6 & 8 \\-14 & 33 \end{bmatrix}-\begin{bmatrix}12 & 5 \\-27 & -8 \end{bmatrix}}\)
- \(\color{blue}{\begin{bmatrix}12 & 21 \\-17 & 33 \end{bmatrix}-\begin{bmatrix}5& -8 \\2 & 19 \end{bmatrix}}\)
- \(\color{blue}{\begin{bmatrix}-5 & 2& -2 \\4 & -2&0 \end{bmatrix}-\begin{bmatrix}6 & -5&-6 \\1 & 3&-3 \end{bmatrix}}\)
- \(\color{blue}{\begin{bmatrix}-6r+t \\-r\\6s \end{bmatrix}+\begin{bmatrix}6r \\-4t\\-3r+2 \end{bmatrix}}\)
- \(\color{blue}{\begin{bmatrix}16 & -4 \\-38 & 24 \end{bmatrix}+\begin{bmatrix}9 & -6 \\5& 2 \end{bmatrix}}\)
- \(\color{blue}{\begin{bmatrix}18 & -5 \\-32 & 14 \end{bmatrix}+\begin{bmatrix}11& -6 \\7 & 2 \end{bmatrix}}\)
- \(\color{blue}{\begin{bmatrix}-4n & n+m \\-2n & -4m\end{bmatrix}+\begin{bmatrix}4 & -5 \\3 & 0 \end{bmatrix}}\)
- \(\color{blue}{\begin{bmatrix}z-5 \\-6\\-1-6z\\3y \end{bmatrix}+\begin{bmatrix}-3y\\3z\\5+z\\4z \end{bmatrix}}\)
Answers to the eight practice problems
- \(\color{blue}{\begin{bmatrix}-6 & 3 \\13 & 41 \end{bmatrix}}\)
- \(\color{blue}{\begin{bmatrix}7 & 29 \\-19 & 14 \end{bmatrix}}\)
- \(\color{blue}{\begin{bmatrix}-11 & 7&4 \\3 & -5&3 \end{bmatrix}}\)
- \(\color{blue}{\begin{bmatrix}t \\-r-4t\\6s-3r+2 \end{bmatrix}} \)
- \(\color{blue}{\begin{bmatrix}25 & -10 \\-33 & 26 \end{bmatrix}}\)
- \(\color{blue}{\begin{bmatrix}29 & -11 \\-25 & 16 \end{bmatrix}}\)
- \(\color{blue}{\begin{bmatrix}-4n+4 & n+m-5 \\-2n+3 & -4m\end{bmatrix}}\)
- \(\color{blue}{\begin{bmatrix}z-5-3y \\-6+3z\\4-5z\\3y+4z \end{bmatrix}} \)
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