10 Most Common HSPT Math Questions

10 Most Common HSPT Math Questions

B. \(132\) cm

C. \(156\) cm

D. \(175\) cm

9-In five successive hours, a car traveled \(40\) km,\(45\) km,\(50\) km,\(35\) km and \(55\) km. In the next five hours, it traveled with an average speed of \(65\) km per hour. Find the total distance the car traveled in \(10\) hours.

A. \(425\) km

B. \(450\) km

C. \(550\) km

D. \(600\) km

10- How long does a \(420\)–miles trip take moving at \(65\) miles per hour (mph)?

A. \( 4\) hours

B. \(4\) hours and \(24\) minutes

C. \(6\) hours and \(24\) minutes

D. \(8\) hours and \(30\) minutes

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Answers:

1- D
Write the equation and solve for \(B\): \(0.60 A=0.20 B\), divide both sides by \(0.20\), then:
\(\frac{0.60}{0.20 } A=B\), therefore: \(B=3A\), and B is \(3\) times of A or it’s \(300\%\) of A.

2- B
Use this formula: Percent of Change \(\frac{New \ Value-Old \ Value}{Old \ Value}×100\% \)
\(\frac{15000-20000}{20000}×100\%=-25\%\) and\(\frac{11200-15000}{15000}×100\%=-25\% \)

3- D
If the length of the box is \(45\), then the width of the box is one-third of it, \(15\), and the height of the box is \(5 \) (one-third of the width). The volume of the box is:
\(V=lwh =(45)(15)(5)=3375\)

4- D
To find the number of possible outfit combinations, multiply the number of options for each factor: \(6×3×5=90\)

5- C
Use simple interest formula: \(I=prt \)(\(I=\)interest,\(p=\)principal,\(r=\)rate,\(t=\)time)
\(I=(8,000)(0.045)(5)=1,800\)

6- B
\(6^4=6×6×6×6=1,296\)

7- C
\(x=\frac{15}{20}=0.75=75\% \)

8- C
The perimeter of the trapezoid is \(56\). Therefore, the missing side (height) is \(=56-18-12-14=12\). Area of a trapezoid: \(A=\frac{1}{2 } h (b_{1}+b_{2})=\frac{1}{2}(12)(12+14)=156\)

9- C
Add the first \(5\) numbers. \(40+45+50+35+55=225\)
To find the distance traveled in the next \(5\) hours, multiply the average by several hours.
Distance\(=\)Average\(×\)Rate \(= 65×5 =325\)
Add both numbers. \(325+225=550\)

10- C
Use distance formula: Distance \(=\)Rate\(×\)time \(⇒ 420=65×T\), divide both sides by \(65. 420÷65=T ⇒ T=6.4\) hours. Change hours to minutes for the decimal part. \(0.4\) hours \(=0.4×60 =24\) minutes.

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