Top 10 8th Grade STAAR Math Practice Questions
C.
D.
5- In the rectangle below if \(y>5\) cm and the area of a rectangle is 50 cm\(^2\) and the perimeter of the rectangle is 30 cm, what is the value of x and y respectively?
A. \(4, 11\)
B. \(5, 11\)
C. \(5, 10\)
D. \(4, 10\)
6- A football team had $40,000 to spend on supplies. The team spent $22,000 on new balls. New sports shoes cost $240 each. Which of the following inequalities represent how many new shoes the team can purchase.
A. \(240x+22,000 ≤40,000 \)
B. \(240x+22,000 ≥40,000\)
C. \(22,000x+240 ≤40,000\)
D. \(22,000x+240 ≥40,000\)
7- Right triangle ABC has two legs of lengths 6 cm (AB) and 8 cm (AC). What is the length of the third side (BC)?
A. 4 cm
B. 6 cm
C. 8 cm
D. 10 cm
8- If \(3x-5=8.5\), What is the value of \(5x+3\)?
A. 13
B. 15.5
C. 20.5
D. 25.5
9- A bank is offering \(4.5\%\) simple interest on a savings account. If you deposit $8,000, how much interest will you earn in five years?
A. $360
B. $720
C. $1800
D. $3600
10- In a party, 10 soft drinks are required for every 12 guests. If there are 252 guests, how many soft drinks is required?
A. 21
B. 105
C. 210
D. 2510
Best 8th Grade STAAR Math Prep Resource for 2026
Answers:
1- C
The weight of 12.2 meters of this rope is: \(12.2 × 600 g = 7320 g\)
\(1 kg = 1000 g\)
therefore,
\(7320 g ÷ 1000 = 7.32 kg\)
2- 600
The ratio of boys to girls is \(3:7\).
Therefore, there are 3 boys out of 10 students. To find the answer, first, divide the number of boys by 3, then multiply the result by 10.
\(180 ÷ 3 = 60 ⇒ 60 × 10 = 600\)
3- C
the population is increased by \(15\%\) and \(20\%\). \(15\%\) increase changes the population to \(115\%\) of the original population.
For the second increase, multiply the result by \(120\%\).
\((1.15) × (1.20) = 1.38 = 138\%\)
38 percent of the population is increased after two years.
4- B
A linear equation is a relationship between two variables, \(x\) and \(y\), that can be put in the form \(y = mx + b\).
A non-proportional linear relationship takes on the form \(y=mx + b\), where \(b ≠ 0\) and its graph is a line that does not cross through the origin.
5- C
The perimeter of the rectangle is: \(2x+2y=30→x+y=15→x=15-y \)
The area of the rectangle is: \(x×y=50→(15-y)(y)=50→y^2-15y+50=0\)
Solve the quadratic equation by factoring method.
\((y-5)(y-10)=0→y=5 \)
(Unacceptable, because y must be greater than 5) or \(y=10\)
If \( y=10 →x×y=50→x×10=50→x=5\)
6- A
Let \(x\) be the number of new shoes the team can purchase. Therefore, the team can purchase \(240 x\).
The team had $40,000 and spent $22,000. Now the team can spend on new shoes $18,000 at most.
Now, write the inequality: \( 120x+22.000 ≤40.000\)
7- D
Use Pythagorean Theorem:
\(a^2 + b^2 = c^2\)
\(6^2 + 8^2 = c^2 ⇒ 100 = c^2 ⇒ c = 10\)
8- D
\(3x-5=8.5→3x=8.5 + 5=13.5→x = \frac{13.5}{3}= 4.5\)
Then;
\(5x+3=5 (4.5)+3=22.5+3=25.5\)
9- C
Use simple interest formula:
\(I=prt\)
\((I = interest, p = principal, r = rate, t = time)\)
\(I=(8000)(0.045)(5)=1800\)
10- C
Let \(x\) be the number of soft drinks for 252 guests. Write the proportion and solve for \(x\).
\(\frac{10 soft drinks}{12 guests}=\frac{x}{252 guests}\)
\(x = \frac{252×10}{12}⇒x=210\)
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