Top 10 8th Grade OST Math Practice Questions

C.

D.

5- In the rectangle below, if \(y>5\) cm and the area of a rectangle is 50 cm\(^2\) and the perimeter of the rectangle is 30 cm, what are the values of x and y, respectively?

A. \(4, 11\)

B. \(5, 11\)

C. \(5, 10\)

D. \(4, 10\)

6- A football team had $40,000 to spend on supplies. The team spent $22,000 on new balls. New sports shoes cost $240 each. Which of the following inequalities represents how many new shoes the team can purchase?

A. \(240x+22,000 ≤40,000 \)

B. \(240x+22,000 ≥40,000\)

C. \(22,000x+240 ≤40,000\)

D. \(22,000x+240 ≥40,000\)

7- Right triangle ABC has two legs of lengths 6 cm (AB) and 8 cm (AC). What is the length of the third side (BC)?

A. 4 cm

B. 6 cm

C. 8 cm

D. 10 cm

8- If \(3x-5=8.5\), What is the value of \(5x+3\)?

A. 13

B. 15.5

C. 20.5

D. 25.5

9- A bank is offering \(4.5\%\) simple interest on a savings account. If you deposit $8,000, how much interest will you earn in five years?

A. $360

B. $720

C. $1800

D. $3600

10- In a party, 10 soft drinks are required for every 12 guests. If there are 252 guests, how many soft drinks is required?

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A. 21

B. 105

C. 210

D. 2510

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Answers:

2- 600
The ratio of boys to girls is \(3:7\).
Therefore, there are 3 boys out of 10 students. To find the answer, first, divide the number of boys by 3, then multiply the result by 10.
\(180 ÷ 3 = 60 ⇒ 60 × 10 = 600\)

3- C
the population is increased by \(15\%\) and \(20\%\). \(15\%\) increase changes the population to \(115\%\) of the original population.
For the second increase, multiply the result by \(120\%\).
\((1.15) × (1.20) = 1.38 = 138\%\)
38 percent of the population is increased after two years.

4- B
A linear equation is a relationship between two variables, \(x\) and \(y\), that can be put in the form \(y = mx + b\).
A non-proportional linear relationship takes on the form \(y=mx + b\), where \(b ≠ 0\) and its graph is a line that does not cross through the origin.

5- C
The perimeter of the rectangle is: \(2x+2y=30→x+y=15→x=15-y \)
The area of the rectangle is: \(x×y=50→(15-y)(y)=50→y^2-15y+50=0\)
Solve the quadratic equation by the factoring method.
\((y-5)(y-10)=0→y=5 \)
(Unacceptable, because y must be greater than 5) or \(y=10\)
If \( y=10 →x×y=50→x×10=50→x=5\)

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6- A
Let \(x\) be the number of new shoes the team can purchase. Therefore, the team can purchase \(240 x\).
The team had $40,000 and spent $22,000. Now the team can spend on new shoe \($18,000\) at most.
Now, write the inequality: \( 120x+22.000 ≤40.000\)

7- D
Use Pythagorean Theorem:
\(a^2 + b^2 = c^2\)
\(6^2 + 8^2 = c^2 ⇒ 100 = c^2 ⇒ c = 10\)

8- D
\(3x-5=8.5→3x=8.5 + 5=13.5→x = \frac{13.5}{3}= 4.5\)
Then;
\(5x+3=5 (4.5)+3=22.5+3=25.5\)

9- C
Use simple interest formula:
\(I=prt\)
\((I = interest, p = principal, r = rate, t = time)\)
\(I=(8000)(0.045)(5)=1800\)

10- C
Let \(x\) be the number of soft drinks for 252 guests. Write the proportion and solve for \(x\).
\(\frac{10 soft drinks}{12 guests}=\frac{x}{252 guests}\)
\(x = \frac{252×10}{12}⇒x=210\)

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