# Top 10 8th Grade ACT Aspire Math Practice Questions

Taking the 8th Grade ACT Aspire Math test? The best way to prepare for your 8th Grade ACT Aspire Math test is to work through as many 8th Grade ACT Aspire Math practice questions as possible. Here are the top 10 8th Grade ACT Aspire Math practice questions to help you review the most important 8th Grade ACT Aspire Math concepts. These 8th Grade ACT Aspire Math practice questions are designed to cover mathematics concepts and topics that are found on the actual test. The questions have been fully updated to reflect the latest 2022 8th Grade ACT Aspire guidelines. Answers and full explanations are provided at the end of the post.

Start your ACT Aspire Math test prep journey right now with these sample ACT Aspire Math questions.

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**8th Grade ACT Aspire Math Practice Questions**

1- A rope weighs \(600\) grams per meter in length. What is the weight in kilograms of \(12.2\) meters of this rope? (\(1\) kilograms \(= 1000\) grams)

A. \(0.0732\)

B. \(0.732\)

C. \(7.32\)

D. \(7320\)

2- In a school, the ratio of the number of boys to girls is \(3:7\). If the number of boys is \(180\), what is the total number of students in the school?__________

Write your answer in the box below.

3- In two successive years, the population of a town is increased by \(15\%\) and \(20\%\). What percent of its population is increased after two years?

A. \(32\)

B. \(35\)

C. \(38\)

D. \(68\)

4- Which graph shows a non–proportional linear relationship between \(x\) and \(y\)?

A.

B.

C.

D.

5- In the rectangle below if \(y>5\) \(cm\) and the area of a rectangle is \(50 cm^2\) and the perimeter of the rectangle is \(30 cm\), what is the value of \(x\) and \(y\) respectively?

A. \(4, 11\)

B. \(5, 11\)

C. \(5, 10\)

D. \(4, 10\)

6- A football team had \($40,000\) to spend on supplies. The team spent \($22,000\) on new balls. New sports shoes cost \($240\) each. Which of the following inequalities represent how many new shoes the team can purchase.

A. \(240x+22,000 ≤40,000 \)

B. \(240x+22,000 ≥40,000\)

C. \(22,000x+240 ≤40,000\)

D. \(22,000x+240 ≥40,000\)

7- Right triangle ABC has two legs of lengths \(6 cm\) (AB) and \(8 cm\) (AC). What is the length of the third side (BC)?

A. \(4 cm\)

B. \(6 cm\)

C. \(8 cm\)

D. \(10 cm\)

8- If \(3x-5=8.5\), What is the value of \(5x+3\)?

A. \(13\)

B. \(15.5\)

C. \(20.5\)

D. \(25.5\)

9- A bank is offering \(4.5\%\) simple interest on a savings account. If you deposit \($8,000\), how much interest will you earn in five years?

A. \($360\)

B. \($720\)

C. \($1800\)

D. \($3600\)

10- In a party, \(10\) soft drinks are required for every \(12\) guests. If there are \(252\) guests, how many soft drinks is required?

A. \(21\)

B. \(105\)

C. \(210\)

D. \(2510\)

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## Answers:

1- **C**

The weight of 12.2 meters of this rope is: \(12.2 × 600 g = 7320 g\)

\(1 kg = 1000 g\)

therefore,

\(7320 g ÷ 1000 = 7.32 kg\)

2- **600**

The ratio of boys to girls is \(3:7\).

Therefore, there are \(3\) boys out of \(10\) students. To find the answer, first, divide the number of boys by \(3\), then multiply the result by \(10\).

\(180 ÷ 3 = 60 ⇒ 60 × 10 = 600\)

3- **C**

the population is increased by \(15\%\) and \(20\%\). \(15\%\) increase changes the population to \(115\%\) of the original population.

For the second increase, multiply the result by \(120\%\).

\((1.15) × (1.20) = 1.38 = 138\%\)

38 percent of the population is increased after two years.

4- **B**A linear equation is a relationship between two variables, \(x\) and \(y\), that can be put in the form \(y = mx + b\).

A non-proportional linear relationship takes on the form \(y=mx + b\), where \(b ≠ 0\) and its graph is a line that does not cross through the origin.

5- **C**

The perimeter of the rectangle is: \(2x+2y=30→x+y=15→x=15-y \)

The area of the rectangle is: \(x×y=50→(15-y)(y)=50→y^2-15y+50=0\)

Solve the quadratic equation by factoring method.

\((y-5)(y-10)=0→y=5 \)

(Unacceptable, because y must be greater than 5) or \(y=10\)

If \( y=10 →x×y=50→x×10=50→x=5\)

6- **A**

Let \(x\) be the number of new shoes the team can purchase. Therefore, the team can purchase \(240 x\).

The team had \($40,000\) and spent \($22,000\). Now the team can spend on new shoe \($18,000\) at most.

Now, write the inequality: \( 120x+22.000 ≤40.000\)

7- **D**

Use Pythagorean Theorem:

\(a^2 + b^2 = c^2\)

\(6^2 + 8^2 = c^2 ⇒ 100 = c^2 ⇒ c = 10\)

8- **D**

\(3x-5=8.5→3x=8.5 + 5=13.5→x = \frac{13.5}{3}= 4.5\)

Then;

\(5x+3=5 (4.5)+3=22.5+3=25.5\)

9- **C**

Use simple interest formula:

\(I=prt\)

\((I = interest, p = principal, r = rate, t = time)\)

\(I=(8000)(0.045)(5)=1800\)

10- **C**

Let \(x\) be the number of soft drinks for \(252\) guests. Write the proportion and solve for \(x\).

\(\frac{10 soft drinks}{12 guests}=\frac{x}{252 guests}\)

\(x = \frac{252×10}{12}⇒x=210\)

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