Pre-Algebra Practice Test Questions

These Pre-Algebra Math practice questions are designed to be similar to those found on the real Pre-Algebra Math test. They will assess your level of preparation and will give you a better idea of what to study for your exam. For additional educational resources, .

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A. 10

B. 12

C. 14

D. 16

6- If \(40\%\) of a number is 4, what is the number?

A. 4

B. 8

C. 10

D. 12

7- The average of five numbers is 24. If a sixth number 42 is added, then, which of the following is the new average?

A. 25

B. 26

C. 27

D. 42

8- The ratio of boys and girls in a class is 4:7. If there are 44 students in the class, how many more boys should be enrolled to make the ratio 1:1?

A. 8

B. 10

C. 12

D. 14

9-What is the slope of the line: \(4x-2y=6\):_______

10- A football team had $20,000 to spend on supplies. The team spent $14,000 on new balls. New sports shoes cost $120 each. Which of the following inequalities represent the number of new shoes the team can purchase.

A. 120\(x\)+14,000 \(\leq \) 20,000

B. 20\(x\)+14,000 \(\geq \) 20,000

C. 14,000\(x\)+120 \(\leq \) 20,000

D. 14,000\(x\)+12,0 \(\geq \) 20,000

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Answers:

2- B
\(Probability = \frac{number \space of \space desired \space outcomes}{number \space of \space total \space outcomes} = \frac{18}{12+18+18+24} = \frac{18}{72} = \frac{1}{4}\)

3- B
The area of the square is 595.36. Therefore, the side of the square is the square root of the area.
\(\sqrt{595.36}=24.4\)
Four times the side of the square is the perimeter:
\(4 {\times} 24.4 = 97.6\)

4- A
The width of the rectangle is twice its length. Let \(x\) be the length. Then, width=\(2x\)
Perimeter of the rectangle is \(2 (width + length) = 2(2x+x)=60 {\Rightarrow} 6x=60 {\Rightarrow} x=10 \)
The length of the rectangle is 10 meters.

5- D
average \(= \frac{sum \space of \space terms}{number \space of \space terms} {\Rightarrow} (average \space of \space 6 \space numbers) \space 12 = \frac{sum \space of \space terms}{6} ⇒sum \space of \space 6 \space numbers\space is \)
\(12 {\times} 6 = 72\)
\((average \space of \space 4 \space numbers) \space 10 = \frac{sum \space of \space terms}{4}{\Rightarrow} sum \space of \space 4 \space numbers \space is \space 10 {\times} 4 = 40\)
sum of 6 numbers – sum of 4 numbers = sum of 2 numbers
\(72 – 40 = 32\)
average of 2 numbers = \(\frac{32}{2} = 16 \)

6- C
Let \(x\) be the number. Write the equation and solve for \(x\).
\(40\% \space of \space x=4{\Rightarrow} 0.40 \space x=4 {\Rightarrow} x=4 {\div}0.40=10\)

7- C
First, find the sum of five numbers.
\(average =\frac{ sum \space of \space terms }{ number \space of \space terms } ⇒ 24 = \frac{ sum \space of \space 5 \space numbers }{5}\)
\( ⇒ sum \space of \space 5 \space numbers = 24 × 5 = 120\)
The sum of 5 numbers is 120. If a sixth number that is 42 is added to these numbers, then the sum of 6 numbers is 162.
120 + 42 = 162
average \(==\frac{ sum \space of \space terms }{ number \space of \space terms } = \frac{162}{6}=27\)

8- C
The ratio of boys to girls is 4:7.
Therefore, there are 4 boys out of 11 students.
To find the answer, first, divide the total number of students by 11, then multiply the result by 4.
\(44 {\div} 11 = 4 {\Rightarrow} 4 {\times} 4 = 16\)
There are 16 boys and 28 \((44 – 16)\) girls. So, 12 more boys should be enrolled to make the ratio 1:1

9- 2
Solve for y.
\(4x-2y=6 {\Rightarrow} -2y=6-4x {\Rightarrow} y=2x-3\)
The slope of the line is 2.

10- A
Let \(x\) be the number of new shoes the team can purchase. Therefore, the team can purchase 120 \(x\).
The team had $20,000 and spent $14000. Now the team can spend on new shoes $6000 at most.
Now, write the inequality:
\(120x+14,000 {\leq}20,000\)

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