Preparing your student for the ISEE Middle-Level Math test? Try these free ISEE Middle-Level Math Practice questions. Reviewing practice questions is the best way to brush up on your student’s Math skills. Here, we walk you through solving 10 common ISEE Middle-Level Math practice problems covering the most important math concepts on the ISEE Middle-Level Math test.

These ISEE Middle-Level Math practice questions are designed to be similar to those found on the real ISEE Middle-Level Math test. They will assess your student’s level of preparation and will give you a better idea of what students need to study for the exam.

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## 10 Sample **ISEE Middle Level** Math Practice Questions

1- What is the greatest common factor of 30 and 48?

A. 6

B. 7

C. 5

D. 8

2- Simplify.

\(2x^2+3y^5-x^2+2z^3-2y^2+2x^3-2y^5+5z^3\)

A. \(3x^2-2y^2+y^5+7z^3\)

B. \( x^2+2x^3-2y^2+y^5+7z^3\)

C. \( x^2+2x^3+3y^5+7z^3\)

D. \(x^2+2x^3-2y^2+5y^5+7z^3\)

3- The ratio of boys and girls in a class is \(4:7\). If there are 44 students in the class, how many more boys should be enrolled to make the ratio \(1:1\)?

A. 8

B. 10

C. 12

D. 16

4- Solve for \(x: 4(x + 1) = 6(x − 4) + 20\)

A. 12

B. 4

C. 6.2

D. 5.5

5- A company pays its employer $7000 plus \(2\%\) of all sales profit. If \(x\) is all sold profit, which of the following represents the employer’s revenue?

A. \(0.02x\)

B. \(0.98x-7000\)

C. \( 0.02x+7000\)

D. \( 0.98x+7000\)

6- Car A uses 8-liter petrol per 100 kilometers; car B use 6-liter petrol per 100 kilometers. If both cars drive 250 kilometers, how much more petrol does car A use?

A. 5

B. 10

C. 15

D. 20

7- \( y=-4x-8\)

A. The quantity in Column A is greater.

B. The quantity in Column B is greater.

C. The two quantities are equal.

D. The relationship cannot be determined from the information given.

8-

A. The quantity in Column A is greater.

B. The quantity in Column B is greater.

C. The two quantities are equal.

D. The relationship cannot be determined from the information given.

9- The average age of Joe, Michelle, and Nicole is 32.

A. The quantity in Column A is greater.

B. The quantity in Column B is greater.

C. The two quantities are equal.

D. The relationship cannot be determined from the information given.

10-

A. The quantity in Column A is greater.

B. The quantity in Column B is greater.

C. The two quantities are equal.

D. The relationship cannot be determined from the information given.

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## Answers:

1- **A**

Prime factorizing of \( 30=2×3×5\)

Prime factorizing of \(48=2×2×2×2×3\)

GCF\(=2×3=6\)

2- **B**

\(2x^2+3y^5-x^2+2z^3-2y^2+2x^3-2y^5+5z^3=\)

\(2x^2-x^2+2x^3-2y^2+3y^5-2y^5+2z^3+5z^3=\)

\(x^2+2x^3-2y^2+y^5+7z^3\)

3-** C**

The ratio of boys to girls is \(4:7\). Therefore, there are 4 boys out of 11 students. To find the answer, first, divide the total number of students by 11, then multiply the result by 4.

\(44 ÷ 11 = 4 ⇒ 4 × 4 = 16\)

There are 16 boys and \(28 (44 – 16)\) girls. So, 12 more boys should be enrolled to make the ratio\( 1:1\)

4- **B**Simplify:

\(4(x + 1) = 6(x − 4) + 20\)

\(4x + 4 = 6x − 24 + 20\)

\(4x + 4 = 6x – 4\)

Subtract \(4x\)from both sides:

\(4 = 2x – 4\)

Add 4 to both sides:

\(8 = 2x\)

\(4 = x\)

5- **C**

Employer’s revenue: \(0.2x+7000\)

6- **A**

Petrol of car A in \(250 \space km = \frac{(8×250)}{100} = 20\)

Petrol of car A in 250 km = \(\frac{(6×250)}{100} = 15\)

\(20-15=5\)

7- **B**

Column A: The value of \(x\) when \(y = 12:\)

\(y=-4x-8→12=-4x-8→-4x=20→x=-5\)

Column \(B: -4\)

\(-4 \space is \space greater \space than \space -5.\)

8- **A**

Column A: Simplify.

\( \sqrt{36}+\sqrt{36}=6+6=12\)

12 is greater than \(\sqrt{72}\) . \((\sqrt{144}=12)\)

9- **D**

Column A: Based on the information provided, we cannot find the average age of Joe and Michelle or the average age of Michelle and Nicole.

10- **A**

Column A: Simplify.

\(\sqrt{(121-64)}=\sqrt{57}\)

Column B:

\(\sqrt{121}-\sqrt{64}=11-8=3 \)

\(\sqrt{57}\) is bigger than 3. \((\sqrt 9 = 3)\)

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