ISEE Middle-Level Math Practice Test Questions

ISEE Middle-Level Math Practice Test Questions

B. The quantity in Column B is greater.

C. The two quantities are equal.

D. The relationship cannot be determined from the information given.

8-

A. The quantity in Column A is greater.

B. The quantity in Column B is greater.

C. The two quantities are equal.

D. The relationship cannot be determined from the information given.

9- The average age of Joe, Michelle, and Nicole is 32.

A. The quantity in Column A is greater.

B. The quantity in Column B is greater.

C. The two quantities are equal.

D. The relationship cannot be determined from the information given.

10-

A. The quantity in Column A is greater.

B. The quantity in Column B is greater.

C. The two quantities are equal.

D. The relationship cannot be determined from the information given.

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Answers:

1- A
Prime factorizing of \( 30=2×3×5\)
Prime factorizing of \(48=2×2×2×2×3\)
GCF\(=2×3=6\)

2- B
\(2x^2+3y^5-x^2+2z^3-2y^2+2x^3-2y^5+5z^3=\)
\(2x^2-x^2+2x^3-2y^2+3y^5-2y^5+2z^3+5z^3=\)
\(x^2+2x^3-2y^2+y^5+7z^3\)

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3- C
The ratio of boys to girls is \(4:7\). Therefore, there are 4 boys out of 11 students. To find the answer, first, divide the total number of students by 11, then multiply the result by 4.
\(44 ÷ 11 = 4 ⇒ 4 × 4 = 16\)
There are 16 boys and \(28 (44 – 16)\) girls. So, 12 more boys should be enrolled to make the ratio\( 1:1\)

4- B
Simplify:
\(4(x + 1) = 6(x − 4) + 20\)
\(4x + 4 = 6x − 24 + 20\)
\(4x + 4 = 6x – 4\)
Subtract \(4x\)from both sides:
\(4 = 2x – 4\)
Add 4 to both sides:
\(8 = 2x\)
\(4 = x\)

5- C
Employer’s revenue: \(0.2x+7000\)

6- A
Petrol of car A in \(250 \space km = \frac{(8×250)}{100} = 20\)
Petrol of car A in 250 km = \(\frac{(6×250)}{100} = 15\)
\(20-15=5\)

7- B
Column A: The value of \(x\) when \(y = 12:\)
\(y=-4x-8→12=-4x-8→-4x=20→x=-5\)
Column \(B: -4\)
\(-4 \space is \space greater \space than \space -5.\)

8- A
Column A: Simplify.
\( \sqrt{36}+\sqrt{36}=6+6=12\)
12 is greater than \(\sqrt{72}\). \((\sqrt{144}=12)\)

9- D
Column A: Based on the information provided, we cannot find the average age of Joe and Michelle or the average age of Michelle and Nicole.

10- A
Column A: Simplify.
\(\sqrt{(121-64)}=\sqrt{57}\)
Column B:
\(\sqrt{121}-\sqrt{64}=11-8=3 \)
\(\sqrt{57}\) is bigger than 3. \((\sqrt 9 = 3)\)

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