How to Solve Venn Diagrams and the Addition Rule?
In a Venn diagram, this might look like this:
(color{blue}{P(A∪B)=P(A)+P(B)})
Venn Diagrams and the Addition Rule, Example 1:
In a group of (103) students, (32) are freshmen and (46) are sophomores. Find the probability that a student picked from this group at random is either a freshman or sophomore.
First, find the probability of freshman and sophomore:
(P( freshman)=frac{32}{103})
(P( sophomores)=frac{46}{103})
Then, use this formula to find the probability of freshman or sophomore: (color{blue}{P (A or B)=P (A)+P (B)})
(P( freshman or sophomore)=frac{32}{103}+frac{46}{103}=frac{32+46}{103}=frac{78}{103}).
Venn Diagrams and the Addition Rule, Example 2:
In a group of (114) students, (41) are juniors, (50) are male, and (23) are male juniors. Find the probability that a student picked from this group at random is either a junior or male.
First, find the probability of juniors, male and male juniors:
(P ( juniors)=frac{41}{114})
(P ( male)=frac{50}{114})
(P (male juniors)=frac{23}{114})
Then, use this formula to find the probability junior or male: (color{blue}{P (A or B)=P (A)+P (B)−P (A and B)})
(P( junior or male )=frac{41}{114}+frac{50}{114}-frac{23}{114}=frac{(41+50)-23}{114}=frac{91-23}{114}=frac{68}{114})
Exercises for Venn Diagrams and the Addition Rule
- We have to draw a card from a well-shuffled (52)-card deck. So what is the chance of getting a diamond or a face card?
- For two events (A) and (B), (P(A)= frac{3}{5}), (P(B) = frac{3}{4}), and (P(A∪B) = frac{5}{6}). Find the probability of (A∩B).
- A glass jar consists of (3) green,(2) red, (3) blue and (4) yellow marbles. If a marble is randomly selected from a jar, how likely is it to be yellow or green?
- A day of the week is chosen at random. What is the probability of choosing on Sunday or Monday?

- (color{blue}{frac{11}{26}})
- (color{blue}{frac{31}{60}})
- (color{blue}{frac{7}{12}})
- (color{blue}{frac{2}{7}})
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