10 Most Common 6th Grade MCAS Math Questions
To prepare for the 6th Grade MCAS exam, your students will need a quick but complete review of all the items tested in addition to studying the content. This review can be done through the 6th Grade MCAS sample practice questions. One of the advantages of this way is that the students will identify their weaknesses while solving these practice questions and will eliminate them. In this article, we try to help your student by providing 10 common questions of the 6th Grade MCAS test and their exact solution.
Make sure to follow some of the related links at the bottom of this post to get a better idea of what kind of mathematics questions your students need to practice.
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10 Sample 6th Grade MCAS Math Practice Questions
What is the equation of a line that passes through points \((0, 4)\) and \((2, 8)\)?
\(y = x\)
\(y = x + 4\)
\(y = 2x + 4\)
\(y = 2x – 4\)
Show answer and explanation
C
The slope of the line is:
\(\frac{y_2-y_1}{x_2-x_1 }= \frac{8 – 4}{2 – 0}=\frac{4}{2}=2\)
The equation of a line can be written as:
\( y-y_0=m(x – x_0 )→y-4 = 2(x – 0)→y-4 = 2x→y = 2x + 4\)
What is the volume of a box with the following dimensions?
Height \(= 6\) cm , Width \(= 7\) cm, Length \(= 9\) cm
\(63 \space cm^3\)
\(126\space cm^3\)
\(189\space cm^3\)
\(378\space cm^3\)
Show answer and explanation
D
Volume of a \(box = length × width × height = 6 × 7 × 9 = 378\)
Anita’s trick–or–treat bag contains 14 pieces of chocolate, 15 suckers, 16 pieces of gum, and 20 pieces of licorice. If she randomly pulls a piece of candy from her bag, what is the probability of her pulling out a piece of sucker?
\(\frac{1}{13}\)
\(\frac{3}{13}\)
\(\frac{14}{65}\)
\(\frac{16}{65}\)
Show answer and explanation
B
\(Probability = \frac{number \space of \space desired \space outcomes}{number \space of \space total \space outcomes}=\frac{15}{14+15+16+20}= \frac{15}{65}=\frac{3}{13}\)
In the following rectangle, which statement is false?
AD is parallel to BC
The measure of the sum of all the angles equals \(360^\circ\).
Length of AB equal to length DC.
AB is perpendicular to AC.
Show answer and explanation
D
In any rectangle, sides are not perpendicular to diagonals.
The area of a rectangular yard is 90 square meters. What is its width if its length is 15 meters?
10 meters
8 meters
6 meters
4 meters
Show answer and explanation
C
Let y be the width of the rectangle. Then; \(15×y=90→y=\frac{90}{15}=6\)
Which statement about 4 multiplied by \(\frac{3}{5}\) must be true?
The product is between 1 and 2
The product is greater than 3
The product is equal to \(\frac{75}{31}\)
The product is between 2 and 2.5
Show answer and explanation
D
\( 4×\frac{3}{5}=\frac{12}{5}=2.4 \)
\( 2.4>2\)
\( 2.4<3\)
\( \frac{75}{31}=2.419≠2.4\)
\(2<2.4<2.5 \) This is the answer!
Which of the following lists shows the fractions in order from least to greatest?
\(\frac{3}{4}, \frac{2}{7}, \frac{3}{8} , \frac{5}{11}\)
\(\frac{3}{8}, \frac{2}{7}, \frac{3}{4}, \frac{5}{11}\)
\(\frac{2}{7}, \frac{5}{11}, \frac{3}{8}, \frac{3}{4}\)
\(\frac{2}{7}, \frac{3}{8}, \frac{5}{11}, \frac{3}{4}\)
\(\frac{3}{8}, \frac{2}{7}, \frac{5}{11}, \frac{3}{4}\)
Show answer and explanation
C
Let’s compare each fraction:
\(\frac{2}{7}< \frac{3}{8}< \frac{5}{11} < \frac{3}{4}\)
Only choice C provides the right order.
A car costing $300 is discounted \(10\%\). Which of the following expressions can be used to find the selling price of the car?
\((300)(0.4)\)
\(300-(300×0.1)\)
\((300)(0.1)\)
\( 300-(300×0.9)\)
Show answer and explanation
B
To find the discount, multiply the number (\(100\%\)- rate of discount)
Therefore; \(300(100\%-10\%)=300(1-0.1)=300-(300×0.1)\)
What is the missing price factor of number 420?
\(420=2^2×3^1×…\)
\(2^2×3^1×5^1×7^1\)
\(2^2×3^1×7^1×9^1\)
\(1^2×2^3×2^1×3^1\)
\(3^2×5^1×7^1×9^1\)
Show answer and explanation
A
\(420=2^2×3^1×5^1×7^1\)
If the area of the following trapezoid is equal to A, which equation represents \(x\)?
\(x = \frac{13}{A}\)
\(x = \frac{A}{13}\)
\( x=A+13\)
\( x=A-13\)
Show answer and explanation
B
The area of the trapezoid is: area= \(\frac{(base 1+base 2)}{2}×height= (\frac{10 + 16}{2})x = A\)
\( →13x = A→x = \frac{A}{13}\)
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