Synthetic Division

Definitionnoun phrase

What is synthetic division?

Synthetic division is a shortcut for dividing a polynomial by a linear factor of the form x − k. You write only the coefficients, bring down the first one, then repeat two moves: multiply by k and add. The bottom row gives the quotient’s coefficients, and its last number is the remainder, which equals the polynomial’s value at k.

In Spanish
división sintética
Also called
synthetic substitution, shortcut polynomial division
Grade level
Algebra 2
Algebra 2PrecalculusCCSS HSA-APR.B.2CCSS HSA-APR.D.6ACTACCUPLACER

Synthetic Division in a picture

Synthetic division of x³ − 4x² + x + 6 by x − 2The coefficients 1, -4, 1, 6 are written in a row with k = 2 in a box. Bringing down, multiplying by 2 and adding gives the bottom row 1, -2, -3 and remainder 0, so the quotient is x squared – 2x – 3.(x³ − 4x² + x + 6) ÷ (x − 2)2k = 211−42−21−4−36−601. Bring down the 1.2. Multiply by k = 2 and write it in the next column (orange).3. Add down the column. Repeat to the end.quotient: x² − 2x − 3remainder: 0Remainder 0, so (x − 2) is a factor and f(2) = 0.
Each column is add, each diagonal is multiply by k. The bottom row, minus its last number, is the quotient; the last number is the remainder.

Formal definition and notation

Let f(x) = an xn + ⋯ + a1 x + a0 be a polynomial and x − k the divisor. Synthetic division finds the quotient q(x), of degree n − 1, and the constant remainder r with f(x) = (x − k)q(x) + r. The first quotient coefficient is an; each next one is the next coefficient of f plus k times the previous result, and the final sum is r. By the Remainder Theorem, r = f(k), so r = 0 exactly when x − k is a factor and k is a zero of f. The method needs a divisor of degree 1 with leading coefficient 1.

Symbol Read it as Meaning
k k the number in the box; for the divisor x − k. For x + 3, k = −3
q(x) q of x the quotient, one degree lower than the dividend
r r the remainder, a number; it equals f(k)

Key facts

  • Write every power in order and put 0 for any missing term: x3 − 7 has coefficients 1, 0, 0, −7.
  • Use the opposite sign of the number in the divisor: x − 5 uses k = 5, and x + 2 uses k = −2.
  • The quotient starts one degree lower: dividing a cubic gives a quadratic.
  • Remainder Theorem: the remainder equals f(k), so synthetic division is also a fast way to evaluate a polynomial.
  • Factor Theorem: remainder 0 means x − k is a factor and k is a zero, which helps with factoring higher-degree polynomials.
  • For a divisor like 2x − 1, use k = 12, then divide the quotient’s coefficients by 2.

What synthetic division gives you

What synthetic division gives you
f(x) = (x − k)q(x) + r, with r = f(k)
f(x)
the polynomial you divide (the dividend)
x − k
the divisor
q(x)
the quotient, read from the bottom row
r
the remainder, the last number in the bottom row

As a fraction: f(x)x − k = q(x) + rx − k. If r = 0, the division comes out even.

Synthetic Division examples, step by step

Example 1: Divide a quadratic

Warm-up

Divide x2 + 5x + 6 by x + 2.

  1. x + 2 = x − (−2), so k = −2. The coefficients are 1, 5, 6.
  2. Bring down 1. Multiply 1 × (−2) = −2; add 5 + (−2) = 3.
  3. Multiply 3 × (−2) = −6; add 6 + (−6) = 0.
  4. The bottom row 1, 3 | 0 means quotient x + 3, remainder 0.

Answer: (x2 + 5x + 6) ÷ (x + 2) = x + 3, with remainder 0.

Example 2: A missing term and a remainder

Core

Divide 2x3 − 5x2 + 4 by x − 3.

  1. There is no x term, so the coefficients are 2, −5, 0, 4, and k = 3.
  2. Bring down 2. 2 × 3 = 6; −5 + 6 = 1.
  3. 1 × 3 = 3; 0 + 3 = 3.
  4. 3 × 3 = 9; 4 + 9 = 13.
  5. Bottom row 2, 1, 3 | 13: quotient 2x2 + x + 3, remainder 13.

Answer: The quotient is 2x2 + x + 3 with remainder 13.

Example 3: Test a possible factor

Test-style

Is x + 1 a factor of p(x) = x4 + 2x3 − x − 2?

  1. Use k = −1 and the coefficients 1, 2, 0, −1, −2.
  2. Bring down 1. Then 2 − 1 = 1, 0 − 1 = −1, −1 + 1 = 0, −2 + 0 = −2.
  3. The remainder is −2, not 0, so by the Remainder Theorem p(−1) = −2.

Answer: No. The remainder is −2, so p(−1) = −2 and x + 1 is not a factor.

Common mistakes

✗ MistakeUsing the coefficients 2, −5, 4 for 2x3 − 5x2 + 4.
✓ InsteadWrite 2, −5, 0, 4, with 0 holding the x place.

Each column stands for one power of x. Skipping a power shifts every later number into the wrong column.

✗ MistakeDividing by x + 3 with 3 in the box.
✓ InsteadUse k = −3, because x + 3 = x − (−3).

The method is built for x − k. The number in the box is the value that makes the divisor zero.

✗ MistakeSubtracting down the columns, as in long division.
✓ InsteadAdd down the columns in synthetic division.

Using k instead of −k already flips the sign, so the subtraction of long division becomes addition.

✗ MistakeReading the bottom row 1, −2, −3 for a cubic as x3 − 2x2 − 3x.
✓ InsteadThe quotient is x2 − 2x − 3.

Dividing by a degree-1 divisor lowers the degree by one, so the first bottom number goes with one power less.

Not to be confused with

Synthetic Divisionvs.Polynomial long division

Long division works for any polynomial divisor, such as x2 + 1, and writes out every term. Synthetic division is a compact shortcut that only works for divisors like x − k.

Synthetic Divisionvs.Remainder theorem

The Remainder Theorem is the fact that dividing f(x) by x − k leaves remainder f(k). Synthetic division is the procedure that finds that remainder quickly.

Synthetic Divisionvs.Factoring

Factoring rewrites a polynomial as a product. Synthetic division is one tool for it: a remainder of 0 hands you a factor x − k and the other factor q(x).

Quick check: 3 questions

Question 1 of 3

To divide by x + 4 with synthetic division, which number goes in the box?

Show answer and explanation

Answer: A. x + 4 = x − (−4), so k = −4, the value that makes x + 4 zero. 4 forgets to change the sign, and 1 and 14 are not zeros of x + 4.

Question 2 of 3

Synthetic division of a cubic by x − k ends with the bottom row 3, −1, 4, 7. What is the result?

Show answer and explanation

Answer: B. The last number is the remainder, 7, and the others are the quotient’s coefficients starting one degree lower: 3x2 − x + 4. The first choice keeps the old degree, the third treats 7 as a term, and the fourth reads the row backward.

Question 3 of 3

What is the remainder when x3 + 2x2 − 5 is divided by x − 2?

Show answer and explanation

Answer: D. By the Remainder Theorem the remainder is f(2) = 8 + 8 − 5 = 11. −5 is just the constant term, 3 comes from forgetting the 0 for the missing x term, and 27 uses k = 3.

Synthetic Division: frequently asked questions

When can you use synthetic division?

Use it when you divide a polynomial by a linear divisor with leading coefficient 1, such as x − 4 or x + 7. With a small change it also handles ax − b: use k = ba and divide the quotient by a. For divisors of degree 2 or more, such as x2 − 3, use polynomial long division instead.

What does the remainder tell you?

The remainder is the value of the polynomial at k: r = f(k). If it is 0, then x − k is a factor and k is a zero, an x-intercept of the graph. If it is not 0, x − k is not a factor, and you can write the result as q(x) + rx − k.

What do you do with missing terms?

Put a 0 in their place. For x4 − 3x + 2, the powers x3 and x2 are missing, so the row is 1, 0, 0, −3, 2. Every power from the highest down to the constant needs its own column, or the multiply-and-add steps will land in the wrong places.

Practice and tools

Sources

  1. Common Core State Standards, High School Algebra, Arithmetic with Polynomials and Rational Expressions (HSA-APR.B.2, HSA-APR.D.6)
  2. OpenStax, College Algebra 2e, 5.4 Dividing Polynomials

Updated November 2026·Reviewed by the Effortless Math team·Standards: CCSS HSA-APR.B.2, CCSS HSA-APR.D.6

Cite this entry

Effortless Math Team. “Synthetic Division.” Effortless Math Dictionary. Updated November 2026. https://www.effortlessmath.com/math-dictionary/synthetic-division/

Flashcard

TermSynthetic Divisionmultiply by k, add, repeat
DefinitionA shortcut for dividing by x − k using only coefficients. (x2 + 5x + 6) ÷ (x + 2): k = −2, quotient x + 3, remainder 0.
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