Independent Events

Definitionnoun phrase

What are independent events in probability?

Independent events are two events where the outcome of one does not change the probability of the other. Flipping heads on a coin does not affect rolling a 5 on a die. For independent events, multiply: P(A and B) = P(A) × P(B), so P(heads and 5) = 12 × 16 = 112.

In Spanish
eventos independientes
Also called
independent event, independence, independent probability
Grade level
Statistics
Grade 7Algebra 1Algebra 2StatisticsCCSS HSS-CP.A.2SATACTGEDASVABHiSETAP

Independent Events in a picture

Independent eventsA 2 by 6 grid of coin and die outcomes with heads-and-5 highlighted as 1 of 12, matching one half times one sixth. Below, drawing twice from a bag of 3 red and 5 blue marbles with replacement is independent (9/64) and without replacement is dependent (3/28).Flip a coin AND roll a die: 2 × 6 = 12 outcomes123456HH1H2H3H4H5H6TT1T2T3T4T5T6P(heads and 5) = 1 of 12 boxesP(H) × P(5) = 1/2 × 1/6 = 1/12Bag: 3 red, 5 blue. Draw twice.put it backkeep it outP(red, red)P(red, red)3/8 × 3/8 = 9/643/8 × 2/7 = 3/28independentdependent
Heads-and-5 is 1 of 12 equally likely outcomes, exactly 12 × 16. Putting a marble back keeps draws independent; keeping it out makes them dependent.

Formal definition and notation

Events A and B are independent if P(A ∩ B) = P(A) · P(B). When P(B) > 0, this is the same as P(A ∣ B) = P(A): knowing that B happened leaves the probability of A unchanged. Events that are not independent are dependent.

Symbol Read it as Meaning
P(A and B) the probability of A and B both events happen; also written P(A ∩ B)
P(A ∣ B) the probability of A given B the probability of A once you know B happened
P(A ∩ B) = P(A)P(B) P of A and B equals P of A times P of B the test for independence

Key facts

  • Ask: does knowing the first result change the chances for the second? If not, the events are independent.
  • Separate coins, dice and spinners are independent. So are draws with replacement, because the bag is reset each time.
  • Draws without replacement are dependent: P(red, red) from 3 red and 5 blue is 38 × 27, not 38 × 38.
  • Past results do not change independent future ones: after five heads in a row, the next flip is still 12 heads.
  • Independent is not the same as mutually exclusive. Two events that cannot both happen (with nonzero probabilities) are always dependent.
  • To test data, compare P(A and B) with P(A) × P(B), for example from a two-way table.

Multiplication rule for independent events

Multiplication rule for independent events
P(A and B) = P(A) × P(B)
P(A)
the probability of the first event
P(B)
the probability of the second event
P(A and B)
the probability that both happen

It extends to more events: three independent coin flips all landing heads is 12 × 12 × 12 = 18. Use it only when the events really are independent.

Independent Events examples, step by step

Example 1: Coin and spinner

Warm-up

A spinner has 4 equal sections, one of them blue. You flip a coin and spin. What is P(tails and blue)?

  1. The coin and the spinner do not affect each other, so the events are independent.
  2. P(tails) = 12 and P(blue) = 14.
  3. Multiply: 12 × 14 = 18.

Answer: P(tails and blue) = 18, or 0.125.

Example 2: With and without replacement

Core

A bag holds 4 green and 6 yellow tiles. You draw two tiles. Find P(green, then green) (a) if you replace the first tile and (b) if you do not.

  1. (a) With replacement the bag is the same each time: 410 × 410 = 16100 = 425.
  2. (b) Without replacement, after one green there are 3 green out of 9: 410 × 39 = 1290 = 215.
  3. Only (a) uses independent events; in (b) the first draw changes the second.

Answer: (a) 425 = 0.16; (b) 215 ≈ 0.133.

Example 3: Test for independence

Test-style

In a school, 40% of students play a sport, 50% are in band, and 20% do both. Are playing a sport and being in band independent?

  1. P(S) = 0.4 and P(B) = 0.5, so P(S) × P(B) = 0.2.
  2. P(S and B) = 0.2.
  3. The two numbers are equal, so the events are independent.
  4. Check another way: P(S ∣ B) = 0.20.5 = 0.4, the same as P(S).

Answer: Yes, they are independent, because 0.4 × 0.5 = 0.2 equals P(both).

Common mistakes

✗ MistakeTwo cards drawn without replacement from a deck: P(ace, ace) = 452 × 452.
✓ Instead452 × 351 = 1221.

Without replacement the second draw has one fewer card and one fewer ace. The events are dependent, so the second probability must change.

✗ MistakeA coin landed heads 5 times in a row, so tails is now more likely.
✓ InsteadP(tails) = 12 on every flip.

Coin flips are independent. The coin has no memory; this mistake is called the gambler’s fallacy.

✗ MistakeFor independent events, P(A and B) = P(A) + P(B).
✓ InsteadMultiply: P(A and B) = P(A) × P(B).

“And” with independent events multiplies. Adding is for “or” with events that cannot happen together, and it can give totals above 1.

Not to be confused with

Independent Eventsvs.Mutually exclusive events

Mutually exclusive events cannot happen together, so P(A and B) = 0. Rolling a 2 and rolling a 5 on one die are mutually exclusive, and therefore dependent: if one happens, the other cannot.

Independent Eventsvs.Dependent events

Dependent events affect each other’s probabilities, like two draws without replacement. Then P(A and B) = P(A) × P(B ∣ A).

Independent Eventsvs.Probability

Probability is the chance of one event; independence describes how two events relate to each other.

Quick check: 3 questions

Question 1 of 3

Which pair of events is independent?

Show answer and explanation

Answer: B. The first roll does not change the second, so two die rolls are independent. The card draws and the student picks remove an option, and rain directly makes the ground wet, so those pairs are dependent.

Question 2 of 3

P(A) = 0.3 and P(B) = 0.6. If A and B are independent, what is P(A and B)?

Show answer and explanation

Answer: B. Multiply: 0.3 × 0.6 = 0.18. 0.9 adds the probabilities, 0.3 is just P(A), and 0.5 is the ratio 0.30.6.

Question 3 of 3

You roll a fair die three times. What is the probability of getting a 6 every time?

Show answer and explanation

Answer: D. The rolls are independent: 16 × 16 × 16 = 1216. 36 adds the probabilities and 118 multiplies 6 by 3 instead of cubing it.

Independent Events: frequently asked questions

How do you know if two events are independent?

Ask whether one outcome changes the chances of the other. If you can compute probabilities, check whether P(A and B) = P(A) × P(B); if the two sides are equal, the events are independent. Another test is P(A ∣ B) = P(A): learning that B happened does not change the probability of A.

What is the difference between independent and mutually exclusive events?

Independent events can happen together and do not affect each other, like a coin flip and a die roll. Mutually exclusive events cannot happen together, like rolling a 1 and a 6 on the same roll. If two events with nonzero probabilities are mutually exclusive, they are dependent, because one happening makes the other impossible.

Is drawing with replacement independent?

Yes. Putting the item back restores the original set, so the second draw has exactly the same probabilities as the first. Without replacement, the set shrinks and its makeup changes, so the second probability depends on what you drew first. That is why without-replacement problems use 38 × 27 instead of 38 × 38.

Practice and tools

Sources

  1. Common Core State Standards, High School Statistics and Probability: Conditional Probability (HSS-CP.A.2)
  2. OpenStax, Introductory Statistics 2e, 3.2 Independent and Mutually Exclusive Events

Updated November 2026·Reviewed by the Effortless Math team·Standards: CCSS HSS-CP.A.2

Cite this entry

Effortless Math Team. “Independent Events.” Effortless Math Dictionary. Updated November 2026. https://www.effortlessmath.com/math-dictionary/independent-events/

Flashcard

TermIndependent EventsP(A)P(B)
DefinitionEvents where one outcome does not change the other’s probability. Multiply: coin heads and die 5 is 12 × 16 = 112.
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