Dependent Events

Definitionnoun phrase

What are dependent events in probability?

Dependent events are two events where the outcome of the first changes the probability of the second. Drawing two cards without putting the first one back is the classic example. For dependent events, P(A and B) = P(A) × P(B ∣ A), where P(B ∣ A) is the probability of B once A has happened.

In Spanish
eventos dependientes
Also called
dependent probability, events that are not independent
Grade level
Statistics
Grade 7Algebra 2StatisticsCCSS 7.SP.C.8CCSS HSS-CP.A.2CCSS HSS-CP.A.3CCSS HSS-CP.B.8SATACTGEDACCUPLACERAP

Dependent Events in a picture

A tree diagram for two dependent drawsA bag has 3 red and 2 blue marbles. A tree shows the first draw (red 3/5, blue 2/5) and the second draw without replacement: after red, red 2/4 and blue 2/4; after blue, red 3/4 and blue 1/4. The red-red path gives 3/5 times 2/4 = 3/10.Bag: 3 red, 2 blue. Draw 2 without replacing.R = red marble, B = blue marble3/52/52/4RR: 3/5 × 2/4 = 6/202/4RB: 3/5 × 2/4 = 6/203/4BR: 2/5 × 3/4 = 6/201/4BB: 2/5 × 1/4 = 2/20RB1st drawafter a red,only 2 of 4 redP(red, then red) = P(R) × P(R | R) = 6/20 = 3/10
The second-draw probabilities change depending on the first draw: 2/4 after a red but 3/4 after a blue. That change is what makes the events dependent. Multiply along a path to get its probability.

Formal definition and notation

Events A and B are dependent when knowing that one occurred changes the probability of the other: P(B ∣ A) ≠ P(B). Equivalently, P(A and B) ≠ P(A) · P(B). Here P(B ∣ A) = P(A and B)P(A), for P(A) > 0, is the conditional probability of B given A. Rearranged, it gives the general multiplication rule, P(A and B) = P(A) · P(B ∣ A), which works for any two events, dependent or not.

Symbol Read it as Meaning
P(B ∣ A) the probability of B given A the probability of B once you know A has happened
P(A and B) the probability of A and B the probability that both happen; also written P(A ∩ B)

Key facts

  • Drawing without replacement makes the draws dependent: the first draw changes what is left. Drawing with replacement keeps them independent.
  • To test two events, compare P(B ∣ A) with P(B). If they differ, the events are dependent.
  • After each draw, both the number of favorable items and the total go down when the first draw was favorable; only the total goes down when it was not.
  • Tree diagrams and two-way tables are the easiest ways to see dependent probabilities.
  • Mutually exclusive events that each have a nonzero probability are always dependent: if one happens, the other has probability 0.

Multiplication rule for dependent events

Multiplication rule for dependent events
P(A and B) = P(A) × P(B ∣ A)
P(A)
the probability of the first event
P(B ∣ A)
the probability of the second event, recomputed after the first has happened

For three draws, keep chaining: P(A and B and C) = P(A) · P(B ∣ A) · P(C ∣ A and B). Each new factor uses what is left.

Dependent Events examples, step by step

Example 1: Two marbles without replacement

Warm-up

A bag holds 4 green and 6 yellow marbles. You draw 2 marbles without replacing the first. What is the probability that both are green?

  1. First draw: P(G) = 410.
  2. One green is gone, so 3 greens are left out of 9 marbles: P(G ∣ G) = 39.
  3. Multiply: 410 × 39 = 1290 = 215.

Answer: P(both green) = 215, about 0.13.

Example 2: Two aces from a deck

Core

Two cards are drawn from a standard 52-card deck without replacement. What is the probability that both are aces?

  1. First card: 4 aces out of 52, so 452.
  2. Second card: 3 aces are left out of 51, so 351.
  3. Multiply: 452 × 351 = 122652 = 1221.

Answer: P(two aces) = 1221, about 0.0045.

Example 3: Test for dependence with data

Test-style

In a class of 30 students, 18 play a sport and 14 play an instrument. Of the 18 who play a sport, 12 also play an instrument. Are the events plays a sport and plays an instrument independent or dependent?

  1. Probability of playing an instrument for the whole class: P(I) = 1430 = 715 ≈ 0.47.
  2. Probability among the athletes: P(I ∣ S) = 1218 = 23 ≈ 0.67.
  3. P(I ∣ S) ≠ P(I): knowing a student plays a sport changes the chance they play an instrument.

Answer: The events are dependent, because P(I ∣ S) = 23 but P(I) = 715.

Common mistakes

✗ MistakeFor two greens without replacement from 4 green and 6 yellow: 410 × 410 = 425.
✓ Instead410 × 39 = 215.

Without replacement, the first green is gone. The second fraction must use what is left: 3 greens out of 9 marbles.

✗ MistakeThinking a coin is more likely to land tails after five heads in a row.
✓ InsteadEach flip is still 1/2 heads, 1/2 tails.

Coin flips are independent. The coin has no memory, so earlier flips cannot change the next one.

✗ MistakeMixing up P(B ∣ A) and P(A ∣ B): the share of athletes who play an instrument, 1218, and the share of musicians who play a sport, 1214.
✓ InsteadP(I ∣ S) = 1218 and P(S ∣ I) = 1214 are different numbers.

The event after the bar is the one you already know happened; it sets the new total in the denominator.

Not to be confused with

Dependent Eventsvs.Independent events

Independent events do not affect each other: rolling a 6 does not change the next roll. Then P(A and B) = P(A) × P(B). Dependent events need P(B ∣ A) in place of P(B).

Dependent Eventsvs.Mutually exclusive events

Mutually exclusive events cannot happen together, so P(A and B) = 0, like rolling a 2 and a 5 on one roll. Dependent events can happen together; one just changes the other’s chance.

Dependent Eventsvs.Conditional probability

Conditional probability, P(B ∣ A), is a number: the chance of B given A. Dependent describes a relationship: the events are dependent when that number differs from P(B).

Quick check: 3 questions

Question 1 of 3

Which pair of events is dependent?

Show answer and explanation

Answer: C. Keeping the first card changes what is left in the deck, so the second draw depends on the first. In the other three, nothing about the first action changes the chances for the second.

Question 2 of 3

A box has 5 red chips and 3 white chips. Two chips are drawn without replacement. What is the probability of red first, then white?

Show answer and explanation

Answer: A. 58 × 37 = 1556. 1564 uses 38 for the second draw, as if the red chip were put back; 27 and 815 do not come from multiplying the two draws.

Question 3 of 3

P(A) = 0.5 and P(B ∣ A) = 0.3. What is P(A and B)?

Show answer and explanation

Answer: D. Multiplication rule: 0.5 × 0.3 = 0.15. 0.8 adds the probabilities, 0.2 subtracts them, and 0.6 divides 0.3 by 0.5.

Dependent Events: frequently asked questions

How do you know if events are dependent or independent?

Ask whether the first event changes the situation for the second. Drawing without replacement, choosing people one at a time, or using survey data where groups differ usually signals dependence. To check with numbers, compare P(B ∣ A) with P(B), or P(A and B) with P(A) × P(B). Equal means independent; different means dependent.

What is the formula for dependent events?

P(A and B) = P(A) × P(B ∣ A). Find the probability of the first event, then find the probability of the second event in the changed situation, and multiply. For example, two kings from a deck without replacement: 452 × 351 = 1221.

Can dependent events be mutually exclusive?

Yes. In fact, two mutually exclusive events that each have a nonzero probability are always dependent. If A happens, B cannot, so P(B ∣ A) = 0, which is different from P(B). Rolling a 1 and rolling a 6 on the same roll are mutually exclusive and dependent.

Practice and tools

Sources

  1. Common Core State Standards, Grade 7 Statistics and Probability (7.SP.C.8)
  2. Common Core State Standards, High School Statistics and Probability, Conditional Probability and the Rules of Probability (HSS-CP.A.2, HSS-CP.A.3, HSS-CP.B.8)
  3. OpenStax, Introductory Statistics 2e, 3.2 Independent and Mutually Exclusive Events

Updated November 2026·Reviewed by the Effortless Math team·Standards: CCSS 7.SP.C.8, CCSS HSS-CP.A.2, CCSS HSS-CP.A.3, CCSS HSS-CP.B.8

Cite this entry

Effortless Math Team. “Dependent Events.” Effortless Math Dictionary. Updated November 2026. https://www.effortlessmath.com/math-dictionary/dependent-events/

Flashcard

TermDependent Eventswithout replacement
DefinitionEvents where the first changes the chance of the second. Two reds from 3 red and 2 blue, no replacing: 35 × 24 = 310.
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