Exterior Angle Theorem
\(∠x\) is the exterior angle. \(∠x + 92 = 180º\) (linear pair of angles) \(∠x =\:180-92 = 88º\) Applying the exterior angle theorem, we get, \(∠y + 41 = 88\) \(∠y = 88-41= 47º\) Exercises for Exterior Angle Theorem What is the value of \(p\) in the triangle? Find \(m∠YDC\). Find \(x\) in the given triangle and […]