Top 10 6th Grade PARCC Math Practice Questions

C.

D.

5- The ratio of boys to girls in a school is \(4:5\). If there are \(765\) students in the school, how many boys are in the school?

A. \(612\)

B. \(510\)

C. \(425\)

D. \(340\)

6- Martin earns \($20\) an hour. Which of the following inequalities represents the amount of time Martin needs to work per day to earn at least \($100\) per day?

A. \(20t≥100\)

B. \(20t≤100\)

C. \(20+t≥100\)

D. \(20+t≤100\)

7- \((55+5)÷12\) is equivalent to …

A. \(60÷3.4\)

B. \( \frac{55}{12}+5\)

C. \((2×2×3×5)÷(3×4)\)

D. \( (2×2×3×5)÷3+4\)

8- What is the value of the expression \(6(2x-3y)+(3-2x)^2\), when \(x=2 \) and \(y=-1\)?

A. \(-23\)

B. \(41\)

C. \(43\)

D. \(49\)

9- Round \(\frac{215}{7}\) to the nearest tenth.

A. \(31\)

B. \(30.8\)

C. \(30.7\)

D. \(30\)

10- A chemical solution contains \(6\%\) alcohol. If there are \(45 ml\) of alcohol, what is the volume of the solution?

A. \(270 ml\)

B. \(420 ml\)

C. \(750 ml\)

D. \(1,200 ml\)

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2- A
\(91: 21 = 13: 3\)
\(13×7=91\)
And \( 3×7=21\)

3- A
\(-60 = 115 – x\)
First, subtract 115 from both sides of the equation. Then:
\(-60 – 115=115 – 115- x→-175 = – x\)
Multiply both sides by \((-1)\):
\(→x = 175\)

4- B
\(-8≤5x-8<2 →\) (add 8 all sides)\(-8+8≤5x-8+8<2+8 →0≤5x<10→\) (divide all sides by 5) \(0≤x<2\)

5- D
The ratio of boys to girls is \(4:5\). Therefore, there are \(4\) boys out of \(9\) students. To find the answer, first, divide the total number of students by \(9\), then multiply the result by \(4\).
\(765 ÷ 9 = 85 ⇒ 85 × 4 = 340\)

6- A
For one hour he earns \($20\), then for \(t\) hours he earns \($20t\). If he wants to earn at least \($100\), therefore, the number of working hours multiplied by \(20\) must be equal to \(100 \) or more than \(100\).
\(20t≥100\)

7- C
\((55+5)÷(12)=(60)÷(12)\)
The prime factorization of \(60\) is: \(2×2×3×5 \)
The prime factorization of \(12\) is: \( 3×4 \)
Therefore: \((60)÷(12)=(2×2×3×5)÷(3×4)\)

8- C

Plug in the value of \(x\) and \(y\) and use the order of operations rule.
\(x=2\) and \(y=-1\)
\(6(2x-3y)+(3-2x)^2=6(2(2)-3(-1))+(3-2(2))^2=6(4+3)+(-1)^2 = 42+1=43\)

9- C
\(\frac{215}{7} ≅ 30.71 ≅ 30.7\)

10- C
\(6\%\) of the volume of the solution is alcohol. Let \(x\) be the volume of the solution.
Then: \(6\% \space of \space x = 45 \space ml ⇒ 0.06 x = 45 ⇒ x = 45 ÷ 0.06 = 750\)

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