# 6th Grade PARCC Math FREE Sample Practice Questions

All parents of students should know that using 6th Grade PARCC Math test sample practice questions will create the necessary self-confidence and awareness in 6th Grade students. In fact, after studying the 6th Grade PARCCmathematical concepts, students should use sample practice questions to find their weaknesses and eliminate them. Therefore, using the realistic 6th Grade PARCCMath sample practice questions that we have prepared in this article can greatly help your student succeed in the6th Grade PARCCMath test.

Start preparing your student for the 2022 PARCC Math test with our free sample practice questions. Also, make sure to follow some of the related links at the bottom of this post to get a better idea of what kind of mathematics questions students need to practice.

**The Absolute Best Book to Ace the PARCC Math Test **

**10 Sample 6th Grade PARCC Math Practice Questions**

1- If the area of the following trapezoid is equal to A, which equation represents \(x\)?

\( \img {https://appmanager.effortlessmath.com/public/images/questions/131313444444444444444444444444444.JPG

} \)

A. \(x = \frac{13}{A}\)

B. \(x = \frac{A}{13}\)

C. \(x=A+13\)

D. \(x=A-13\)

2- By what factor did the number below change from the first to the fourth number?

\(8, 104, 1352, 17576\)

A. 13

B. 96

C. 1456

D. 17568

3- 170 is equal to …

A. \(-20-(3×10)+(6×40)\)

B. \(((\frac{15}{8})×72 )+ (\frac{125}{5}) \)

C. \(((\frac{30}{4} + \frac{15}{2})×8) – \frac{11}{2} + \frac{222}{4}\)

D. \(\frac{481}{6} + \frac{121}{3}+50\)

4- The distance between the two cities is 3,768 feet. What is the distance of the two cities in yards?

A. 1,256 yd

B. 11,304 yd

C. 45,216 yd

D. 3,768 yd

5- Mr. Jones saves $3,400 out of his monthly family income of $74,800. What fractional part of his income does Mr. Jones save?

A. \(\frac{1}{22}\)

B. \(\frac{1}{11}\)

C. \(\frac{3}{25}\)

D. \(\frac{2}{15}\)

6- What is the lowest common multiple of 12 and 20?

A. 60

B. 40

C. 20

D. 12

7- Based on the table below, which expression represents any value of f in terms of its corresponding value of \(x\)?

\( \img {https://appmanager.effortlessmath.com/public/images/questions/28282828288888888888888888888888888888888.JPG

} \)

A. \(f=2x-\frac{3}{10}\)

B. \(f=x+\frac{3}{10}\)

C. \(f=2x+2 \frac{2}{5}\)

D. \(2x+\frac{3}{10}\)

8- Solve: 96 kg = … ?

A. 96 mg

B. 9,600 mg

C. 960,000 mg

D. 96,000,000 mg

9- Calculate the approximate area of the following circle? (the diameter is 25)

\( \img {https://appmanager.effortlessmath.com/public/images/questions/3030303000000000000000000000000000.JPG

} \)

A. 78

B. 491

C. 157

D. 1963

10- The following graph shows the mark of six students in mathematics. What is the mean (average) of the marks?

\( \img {https://appmanager.effortlessmath.com/public/images/questions/313131313131111111111111111111111111111111111111.JPG

} \)

A. 13

B. 13.5

C. 14

D. 1.5

**Best 6th Grade PARCC Math Exercise Resource for 2022**

## Answers:

1- **B**

The area of the trapezoid is: area\(= \frac{(base \space 1+base \space 2)}{2}×\)height\(= (\frac{10 + 16}{2})x = A\)

\( →13x = A→x = \frac{A}{13}\)

2- **A**

\(\frac{104}{8}=13, \frac{1352}{104}=13, \frac{17576}{1352}=13\)

Therefore, the factor is 13

3-** C**

Simplify each option provided.

A. \(-20-(3×10)+(6×40)=-20-30+240=190\)

B. \((\frac{15}{8})×72 + (\frac{125}{5}) =135+25=160\)

C. \(((\frac{30}{4} + \frac{15}{2})×8) – \frac{11}{2} + \frac{222}{4} = ((\frac{30 + 30}{4})×8)- \frac{11}{2}+ \frac{111}{2}=(\frac{60}{4})×8) + \frac{100}{2}= 120 + 50 = 170\)

this is the answer

D. \(\frac{481}{6} + \frac{121}{3}+50= \frac{481+242}{6}+50=120.5+50=170.5\)

4- **A**1 yard \(= 3\) feet

Therefore, \(3,768 \space ft × \frac{1 \space yd }{3 \space ft}=1,256 \space yd\)

5- **A**

3,400 out of 74,800 equals to \(\frac{3,400}{74,800}=\frac{17}{374}=\frac{1}{22}\)

6- **A**

Prime factorizing of \(20=2×2×5\)

Prime factorizing of \(12=2×2×3\)

LCM\(=2×2×3×5=60\)

7- **C**

Plugin the value of \(x\) into the function f. First, plug in 3.1 for\( x\).

A. \(f=2x-\frac{3}{10}=2(3.1)-\frac{3}{10}=5.9≠8.6\)

B. \(f=x+\frac{3}{10}=3.1+\frac{3}{10}=3.4≠10.8\)

C. \(f=2x+2 \frac{2}{5}=2(3.1)+2 \frac{2}{5}=6.2+2.4=8.6\)

This is correct!

Plug in other values of \(x. (x=4.2)\)

\(f=2x+2\frac{2}{5} =2(4.2)+2.4=10.8 \)

This one is also correct.

\(x=5.9\)

\(f=2x+2 \frac{2}{5}=2(5.9)+2.4=14.2 \)

This one works too!

D. \(2x+\frac{3}{10}=2(3.1)+\frac{3}{10}=6.5≠8.6\)

8- **D**

1 kg\(= 1000\) g and 1 g \(= 1000\) mg

\(96\) kg\(= 96 × 1000\) g \(= 96 × 1000 × 1000 = 96,000,000\) mg

9- **B**

The diameter of a circle is twice the radius. Radius of the circle is \(\frac{25}{2}\).

Area of a circle = \(πr^2=π(\frac{25}{2})^2=156.25π=156.25×3.14=490.625≅491\)

10- **B**

Average (mean) \(=\frac{sum \space of \space terms}{number \space of \space terms}= \frac{10+11+15+14+15+17+12.5}{7}=13.5\)

** Looking for the best resource to help you succeed on the PARCC Grade 6 Math test?**

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