# Top 10 6th Grade PARCC Math Practice Questions

If all you need is a set of 6th Grade PARCC Math practice questions to help your 6th Grade student practice more, you are in the right place! We help your students to succeed in the 6th Grade PARCC Math exam by providing the top 10 6th Grade PARCC Math Practice questions along with their exact solutions. In fact, this article contains 10 common questions that will help the students identify strengths and weaknesses before the 6th Grade PARCC Math test.

Make sure to follow some of the related links at the bottom of this post to get a better idea of what kind of mathematics questions students need to practice.

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**6th Grade PARCC Math Practice Questions**

1- Which expression is equivalent to \(5(12x-16)\)?

A. \(-20\)

B. \(-20x\)

C. \(60x – 16\)

D. \(60x – 80\)

2- To produce a special concrete, for every \(13\) kg of cement, \(3\) liters of water is required. Which of the following ratios is the same as the ratio of cement to liters of water?

A. \(91: 21\)

B. \(14: 4\)

C. \(39: 6\)

D. \(9: 39\)

3- What is the value of \(x\) in the following equation: \(-60=115-x\)

A. \(175\)

B. \(-175\)

C. \(55\)

D. \(-55\)

4- Which of the following graphs represents the following inequality?

\(-8≤5x-8≤2\)

A.

B.

C.

D.

5- The ratio of boys to girls in a school is \(4:5\). If there are \(765\) students in the school, how many boys are in the school?

A. \(612\)

B. \(510\)

C. \(425\)

D. \(340\)

6- Martin earns \($20\) an hour. Which of the following inequalities represents the amount of time Martin needs to work per day to earn at least \($100\) per day?

A. \(20t≥100\)

B. \(20t≤100\)

C. \(20+t≥100\)

D. \(20+t≤100\)

7- \((55+5)÷12\) is equivalent to …

A. \(60÷3.4\)

B. \( \frac{55}{12}+5\)

C. \((2×2×3×5)÷(3×4)\)

D. \( (2×2×3×5)÷3+4\)

8- What is the value of the expression \(6(2x-3y)+(3-2x)^2\), when \(x=2 \) and \(y=-1\)?

A. \(-23\)

B. \(41\)

C. \(43\)

D. \(49\)

9- Round \(\frac{215}{7}\) to the nearest tenth.

A. \(31\)

B. \(30.8\)

C. \(30.7\)

D. \(30\)

10- A chemical solution contains \(6\%\) alcohol. If there are \(45 ml\) of alcohol, what is the volume of the solution?

A. \(270 ml\)

B. \(420 ml\)

C. \(750 ml\)

D. \(1,200 ml\)

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## Answers:

1- **D**

\(5(12x-16)=(5×12x)-(5×16)=(5×12)x-(5×16)=60x-80\)

2- **A**

\(91 : 21 = 13 : 3\)

\(13×7=91\)

And \( 3×7=21\)

3- **A**

\(-60 = 115 – x\)

First, subtract 115 from both sides of the equation. Then:

\(-60 – 115=115 – 115- x→-175 = – x\)

Multiply both sides by \((-1)\):

\(→x = 175\)

4- **B**

\(-8≤5x-8<2 →\) (add 8 all sides)\(-8+8≤5x-8+8<2+8 →0≤5x<10→\) (divide all sides by 5) \(0≤x<2\)

5- **D**

The ratio of boys to girls is \(4:5\). Therefore, there are \(4\) boys out of \(9\) students. To find the answer, first, divide the total number of students by \(9\), then multiply the result by \(4\).

\(765 ÷ 9 = 85 ⇒ 85 × 4 = 340\)

6- **A**

For one hour he earns \($20\), then for \(t\) hours he earns \($20t\). If he wants to earn at least \($100\), therefore, the number of working hours multiplied by \(20\) must be equal to \(100 \) or more than \(100\).

\(20t≥100\)

7- **C**

\((55+5)÷(12)=(60)÷(12)\)

The prime factorization of \(60\) is: \(2×2×3×5 \)

The prime factorization of \(12\) is: \( 3×4 \)

Therefore: \((60)÷(12)=(2×2×3×5)÷(3×4)\)

8- **C**

Plug in the value of \(x\) and \(y\) and use the order of operations rule.

\(x=2\) and \(y=-1\)

\(6(2x-3y)+(3-2x)^2=6(2(2)-3(-1))+(3-2(2))^2=6(4+3)+(-1)^2 = 42+1=43\)

9- **C**

\(\frac{215}{7} ≅ 30.71 ≅ 30.7\)

10- **C**

\(6\%\) of the volume of the solution is alcohol. Let \(x\) be the volume of the solution.

Then: \(6\% \space of \space x = 45 \space ml ⇒ 0.06 x = 45 ⇒ x = 45 ÷ 0.06 = 750\)

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