Top 10 5th Grade PARCC Math Practice Questions

A. \(8 π\)

B. \(16 π\)

C. \(32 π\)

D. \(64 π\)

8- A rope weighs 800 grams per meter of length. What is the weight in kilograms of 12.2 meters of this rope? (1 kilograms = 1000 grams)

A. 0.0976

B. 0.976

C. 9.76

D. 9760

9- Solve.
\(\frac{1}{2} + \frac{4}{5} – \frac{3}{10} =?\)

A. \(\frac{9}{10}\)

B. \(\frac{2}{10}\)

C. 1

D. 2

10- How many \(\frac{1}{4}\) cup servings are in a package of cheese that contains \(6 \frac{1}{2}\) cups altogether?_________

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Answers:

2- B
\(\frac{3}{11}\) means 3 is divided by 11. The fraction line simply means division or \(÷\). Therefore, we can write \(\frac{3}{11}\) as \(3 ÷ 11\).

3- A
Plugin 20 for A in the equations. Only option A works.
\(A+20=40\)
\(20+20=40\)

4- D
50 miles: 1 hour
425 miles: \(425 ÷ 50 = 8.5\) hours

5- C
Use percent formula:
\(part =\frac{percent}{100}× whole\)
\(50=\frac{percent}{100}× 40⇒ 50 = \frac{percent ×40}{100}⇒ 50 = \frac{percent ×4}{10}\)
multiply both sides by 10.
500 = percent \(×4\), divide both sides by 4.
125 = percent

6- 104
First, find the missing side of the trapezoid. The perimeter of the trapezoid below is 52. Therefore, the missing side of the trapezoid (its height) is: \(52-12-18-14=52-44=8\)
Area of a trapezoid: \(A = \frac{1}{2} h (b_{1} + b_{2}) = \frac{1}{2} (8) (12 + 14) = 104\)

7- B
Use area and circumference of a circle formula.
Area of a circle = \(πr^2 ⇒ 64π = πr^2 ⇒ r= 8\)
Circumference of a circle = \(2πr ⇒ C = 2×8×π ⇒ C =16π\)

8- C
1 meter of the rope = 800 grams 12.2 meter of the rope = \(12.2 × 800 =9,760 \)grams = 9.76 kilograms

9- C
\(\frac{1}{2} + \frac{4}{5} – \frac{3}{10} = \frac{(5×1)+(2×4)-(1×3)}{10} =\frac{10}{10}=1\)

10- 26
To solve this problem, divide \(6\frac{1}{2}\) by \(\frac{1}{4}\).
\(6\frac{1}{2}÷\frac{1}{4}=\frac{13}{2}÷\frac{1}{4}=\frac{13}{2}×\frac{4}{1}=26\)

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