TExES Core Math FREE Sample Practice Questions
Preparing for the TExES Core Math test? To do your best on the TExES Core Math test, you need to review and practice real TExES Math questions. There’s nothing like working on TExES Math sample questions to hone your math skills and put you more at ease when taking the TExES Core Math test. The sample math questions you’ll find here are brief samples designed to give you the insights you need to be as prepared as possible for your TExES Core Math test.
Check out our sample TExES Math practice questions to find out what areas you need to practice more before taking the TExES Core Math test!
Start preparing for the 2026 TExES Math test with our free sample practice questions. Also, make sure to follow some of the related links at the bottom of this post to get a better idea of what kind of mathematics questions you need to practice.
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12
C. 14
D. 16
6- If \(40\%\) of a number is 4, what is the number?
A. 4
B. 8
C. 10
D. 12
7- The average of five numbers is 24. If a sixth number 42 is added, then, which of the following is the new average?
A. 25
B. 26
C. 27
D. 42
8- The ratio of boys and girls in a class is 4:7. If there are 44 students in the class, how many more boys should be enrolled to make the ratio 1:1?
A. 8
B. 10
C. 12
D. 14
9- What is the slope of the line: \(4x-2y=6\)? __________
10- A football team had $20,000 to spend on supplies. The team spent $14,000 on new balls. New sports shoes cost $120 each. Which of the following inequalities represent the number of new shoes the team can purchase.
A. \(120x+14,000 ≤ 20,000\)
B. \(20x+14,000 ≥ 20,000\)
C. \(14,000x+120 ≤ 20,000\)
D. \(14,000x+12,0 ≥ 20,000\)
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Answers:
1- 60
Jason needs a score of 75 on average to pass five exams. Therefore, the sum of 5 exams must be at least \(5 \times 75 = 375\)
The sum of 4 exams is:
\(68 + 72 + 85 + 90 = 315\).
The minimum score Jason can earn on his fifth and final test to pass is:
\(375 – 315 = 60\)
2- B
Probability \(= \frac{number \space of \space desired \space outcomes}{number \space of \space total \space outcomes} = \frac{18}{12+18+18+24} = \frac{18}{72} = \frac{1}{4}\) For additional educational resources, visit the U.S. Department of Education website.
3- B
The area of the square is 595.36. Therefore, the side of the square is a square root of the area.
\(\sqrt{595.36}=24.4\)
Four times the size of the square is the perimeter:\(4 \times 24.4 = 97.6\) For additional educational resources, visit the U.S. Department of Education website.
4- A
The width of the rectangle is twice its length. Let \(x\) be the length. Then, width \(=2x\)
Perimeter of the rectangle is (2 (width + length) \(= 2(2x+x)=60 {\Rightarrow} 6x=60 {\Rightarrow} x=10\)
The length of the rectangle is 10 meters. For additional educational resources, visit the U.S. Department of Education website.
5- D
average \(= \frac{sum \space of \space terms}{number \space of \space terms} {\Rightarrow} (average \space of \space 6 \space numbers) \space 12 = \frac{sum \space of \space terms}{6} ⇒\) sum of 6 numbers is
\(12 {\times} 6 = 72\)
(average of 4 numbers) 10 \(= \frac{sum \space of \space terms}{4}{\Rightarrow}\) sum of 4 numbers is \(10 {\times} 4 = 40\)
sum of 6 numbers \(-\) sum of 4 numbers = sum of 2 numbers
\(72 – 40 = 32\)
average of 2 numbers \(= \frac{32}{2} = 16 \) For additional educational resources, visit the U.S. Department of Education website.
6- C
Let \(x\) be the number. Write the equation and solve for \(x\).
\(40\%\) of \(x=4{\Rightarrow} 0.40 x=4 {\Rightarrow} x=4 {\div}0.40=10\) For additional educational resources, visit the U.S. Department of Education website.
7- C
First, find the sum of five numbers.
average \(=\frac{ sum \space of \space terms }{ number \space of \space terms } ⇒ 24 = \frac{ sum \space of \space 5 \space numbers }{5}
⇒\) sum of 5 numbers \(= 24 × 5 = 120\)
The sum of 5 numbers is 120. If a sixth number that is 42 is added to these numbers, then the sum of 6 numbers is 162.
\(120 + 42 = 162\)
average \(=\frac{ sum \space of \space terms }{ number \space of \space terms } = \frac{162}{6}=27\) For additional educational resources, visit the U.S. Department of Education website.
8- C
The ratio of boy to girls is 4:7.
Therefore, there are 4 boys out of 11 students.
To find the answer, first, divide the total number of students by 11, then multiply the result by 4.
\(44 {\div} 11 = 4 {\Rightarrow} 4 {\times} 4 = 16\)
There are 16 boys and \(28 (44 – 16)\) girls. So, 12 more boys should be enrolled to make the ratio 1:1 For additional educational resources, visit the U.S. Department of Education website.
9- 2
Solve for \(y\).
\(4x-2y=6 {\Rightarrow} -2y=6-4x {\Rightarrow} y=2x-3\)
The slope of the line is 2. For additional educational resources, visit the U.S. Department of Education website.
10- A
Let \(x\) be the number of new shoes the team can purchase. Therefore, the team can purchase \(120 x\).
The team had $20,000 and spent $14000. Now the team can spend on new shoes $6000 at most.
Now, write the inequality:
\(120x+14,000 {\leq}20,000\) For additional educational resources, visit the U.S. Department of Education website.
Looking for the best resource to help you succeed on the TExES Core Math test? For additional educational resources, visit the U.S. Department of Education website.
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