 Did you take the 6th Grade ACT Aspire Math Practice Test? If so, then it’s time to review your results to see where you went wrong and what areas you need to improve.

1- Choice B is correct
Plug in the value of $$x$$ and $$y$$ and use order of operations rule. $$x=2$$ and $$y=-3$$
$$5(4x-3y)-7y^2=5(4(2)-3(-3))-7(-3)^2=5(8+9)-7(9)=5(17)-63=85-63=22$$

2- Choice C is correct
For one hour he earns $18, then for t hours he earns$18t. If he wants to earn at least \$78, therefor, the number of working hours multiplied by 18 must be equal to 78 or more than 78.
$$18t≥78$$

3- Choice B is correct
$$(108-(3×9))÷9=9^3÷81=9$$

4- Choice B is correct
The ratio of boy to girls is 3 ∶ 5. Therefore, there are 3 boys out of 8 students. To find the answer, first divide the total number of students by 8, then multiply the result by 3.
$$240÷8=30 ⇒ 30×3=90$$

5- Choice A is correct
Probability$$=\frac{number \space of \space desired \space outcomes}{number \space of \space total \space outcomes}=\frac{9}{9+15+14+16}=\frac{9}{54}\frac{1}{6}=0.16$$

6- Choice D is correct
Let’s compare each fraction: $$\frac{2}{3}<\frac{3}{4}<\frac{7}{9}<\frac{4}{5}$$ Only choice D provides the right order.

7- Choice B is correct
Let $$y$$ be the width of the rectangle. Then; $$14×y=84→y=\frac{84}{16}=6$$

8- Choice B is correct
$$4×\frac{5}{16}=\frac{20}{16}=1.25$$
A. $$1.25>2$$
B. $$1<1.25<2$$ This is the answer!
C. $$\frac{3}{8}=1.25$$
D. $$1.25=2^2$$

9- Choice B is correct
In any rectangle, The measure of the sum of all the angles equals $$180^\circ$$.

10- Choice C is correct
$$\frac{824}{17}=48.5$$

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11- Choice B is correct
The area of the trapezoid is: Area $$=\frac{base \space 1+base \space 2}{2}×height=\frac{12+10}{2}x=A→ 11x=A→x=\frac{A}{11}$$

12- Choice B is correct
$$\frac{72}{8}=9, \frac{648}{72}=9, \frac{5,832}{648}=9$$, Therefore, the factor is 9.

13- Choice C is correct
Simplify each option provided.
A. $$13-(3×6)+(7×(-6))=13-18+(-42)=-5-42=-47$$
B. $$(\frac{25}{400})+(\frac{7}{50})=\frac{25}{400}+\frac{56}{400}=\frac{81}{400}$$
C. $$((22×\frac{30}{6})-(7×\frac{144}{12}))×\frac{18}{2}=(110-84)×9=26×9=234$$ (this is the answer)
D. $$(\frac{6}{24}+\frac{12}{33})-50=(\frac{1}{4}+\frac{1}{3})-50=(\frac{3}{12}+\frac{4}{12})-50=\frac{7}{12}-50=\frac{-593}{15}$$

14- Choice D is correct
To find the discount, multiply the number ($$100\%$$- rate of discount)
Therefore; $$450(100\%-16\%)=450(1-0.16)=450-(450×0.16)$$

15- Choice A is correct
1,400 out of 11,900 equals to $$\frac{1,400}{11,900}=\frac{200}{1,700}=\frac{2}{17}$$

16- Choice C is correct
The opposite of Nicolas’s integer is $$25$$. So, the integer is $$-25$$. The absolute value of $$25$$ is also $$25$$.

17- Choice C is correct
1 yard = 3 feet, Therefore, $$33,759 ft×\frac{1 \space yd}{3 \space ft}=11,253$$ yd

18- Choice B is correct
$$16\%$$ of the volume of the solution is alcohol. Let $$x$$ be the volume of the solution.
Then: $$16\%$$ of $$x=38$$ ml ⇒ $$0.16x=38 ⇒ x=38÷0.16=237.5$$

19- Choice C is correct
$$(-2)(9x-8)=(-2)(9x)+(-2)(-8)=-18x+16$$

20- Choice D is correct
1 pt = 16 fluid ounces. $$576÷16=36$$
Then: 576 fluid ounces = 36 pt

21- Choice D is correct
1 kg = 1000 g and 1 g = 1000 mg,
120 kg = 120 × 1000 g = 120 × 1000 × 1000 = 120,000,000 mg

22- Choice C is correct
The diameter of a circle is twice the radius. Radius of the circle is $$\frac{14}{2}=7$$.
Area of a circle $$= πr^2=π(7)^2=49π=49×3.14=153.86≅153.9$$

23- Choice B is correct
Average (mean) $$=\frac{sum \space of \space terms}{number \space of \space terms}=\frac{15+17+12+16+21+23}{6}=\frac{104}{6}=17.33$$

24- Choice C is correct
Prime factorizing of $$18=2×3×3$$, Prime factorizing of $$24=2×2×2×3$$
LCM $$= 2×2×2×3×3=72$$

25- Choice B is correct
The coordinate plane has two axes. The vertical line is called the $$y$$-axis and the horizontal is called the $$x$$-axis. The points on the coordinate plane are address using the form $$(x,y)$$. The point A is one unit on the left side of $$x$$-axis, therefore its $$x$$ value is 4 and it is two units up, therefore its $$y$$ axis is 2. The coordinate of the point is: (4, 2)

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26- Choice B is correct
$$α$$ and $$β$$ are supplementary angles. The sum of supplementary angles is 180 degrees.
$$α+β=180^\circ→α=180^\circ-β=180^\circ-125^\circ=55^\circ,$$ Then, $$\frac{α}{β}=\frac{55}{125}=\frac{11}{25}$$

27- Choice C is correct
Opposite number of any number $$x$$ is a number that if added to $$x$$, the result is 0. Then:
$$7+(-7)=0$$ and $$4+(-4)=0$$

28- Choice D is correct
$$-5<2x+7≤3$$→ (add ($$-7$$)all sides) $$(-7)+(-5)<2x+7+(-7)≤3+(-7)$$ →$$-12<2x≤-4$$→(divide all sides by 2),$$-6<x≤-2$$
In inequality $$-6<x≤-2$$, $$x$$ is fewer or equal to $$-2$$ and more than $$-6$$. Only choice D represent the same inequality on the number line.

29- Choice B is correct
A. Number of books sold in April is: $$690$$
Number of books sold in July is: $$1,150→ \frac{690}{1,150}≠2$$
B. Number of books sold in July is: $$1,150$$
Half the number of books sold in May is: $$\frac{1,150}{2}=575→690>575$$ (it’s correct)
C. Number of books sold in June is: $$375$$
Half the number of books sold in April is: $$\frac{690}{3}=230→240<375$$
D. $$690+375=1,065>1,150$$

30- Choice B is correct
$$51∶18=17∶6, 17×3=51$$ and $$8×3=18$$

$$-60=115-x$$; First, subtract 115 from both sides of the equation. Then:
$$-60-115=115-115-x→-175=-x$$, Multiply both sides by ($$-1$$):
→$$x=175$$

The ratio of boy to girls is 4 : 5. Therefore, there are 4 boys out of 9 students. To find the answer, first divide the total number of students by 9, then multiply the result by 4.
$$765 ÷ 9 = 85 ⇒ 85 × 4 = 340$$

Plug in the value of $$x$$ and $$y$$ and use order of operations rule. $$x=2$$ and $$y=-1$$
$$6(2x-3y)+(3-2x)^2=6(2(2)-3(-1))+(3-2(2))^2=6(4+3)+(-1)^2 = 42+1=43$$

$$\frac{215}{7}≅30.71≅30.7$$

Volume of a box $$= ength×width×height=6×7×9=378$$

Let y be the width of the rectangle. Then; $$15×y=90→y=\frac{90}{15}=6$$

$$420=2^2×3^1×5^1×7^1$$

$$\frac{104}{8}=13, \frac{1,352}{104}=13, \frac{17,576}{1,352}=13$$
Therefore, the factor is 13

1 yard = 3 feet
Therefore, $$3,768 ft.×\frac{1 \space yd}{3 \space ft}=1,256 \space yd$$

Prime factorizing of $$20=2×2×5$$
Prime factorizing of $$12=2×2×3$$
LCM $$=2×2×3×5=60$$

The diameter of a circle is twice the radius. Radius of the circle is $$\frac{25}{2}$$.
Area of a circle $$= πr^2=π(\frac{25}{2})^2=156.25π=156.25×3.14=490.625≅491$$

Average (mean) $$= \frac{sum \space of \space terms}{number \space of \space terms}=\frac{10+11+15+14+15+17+12.5}{7}=13.5$$

Since, E is the midpoint of AB, then the area of all triangles DAE, DEF, CFE and CBE are equal.
Let x be the area of one of the triangle, then:
$$4x=140→x=35$$
The area of DEC $$=2x=2(35)=70$$

The perimeter of rectangle is: $$2×(4+7)=2×11=22$$
The perimeter of circle is: $$2πr=2×3×\frac{10}{2}=30$$
Difference in perimeter is: $$30-22=8$$

Find the difference of each pairs of numbers:
2, 3, 5, 8, 12, 17, 23, _, 38
The difference of 2 and 3 is 1, 3 and 5 is 2, 5 and 8 is 3, 8 and 12 is 4, 12 and 17 is 5, 17 and 23 is 6, 23 and next number should be 7. The number is 23 + 7 = 30

46- The answer is $$-122$$.
Use PEMDAS (order of operation):
$$[6 × (–24) + 8] – (–4) + [4 × 5] ÷ 2 = [–144 + 8] – (–4) +  ÷ 2 = [–144 + 8] – (–4) + 10 = [–136] – (–4) + 10 = [–136] + 4 + 10 = –122$$

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