Applying Floor And Ceiling Functions: Practical Examples And Solutions
Applying Floor And Ceiling Functions: Practical Examples And Solutions is a multiple-choice math challenge from Effortless Math. Read the problem, choose from the answer options below, then open the solution to see the full step-by-step working and check your reasoning against it.
( |-3|=3 ), ( |-e|=e )
So in general form, ( |x|=x ) for (x≥0 ) and ( |x|=-x for x<0). The graph of absolute value function, looks like the letter “V”:
Floor function:
Brackets, or brackets without the bent tops ( “⌊…⌋” ) are the mathematical symbol for floor function. This function rounds the number inside it down to the nearest integer. Meaning if you have a positive number with decimals, it omits the decimal and returns the integer that remains. And if the number is negative, it omits the decimal and also subtracts the result by ( 1), thus rounding it down, since more negative means a smaller number.
For example:
( ⌊3.3⌋=3, ⌊ 6.01⌋=6, ⌊ -2.1⌋=-3, ⌊ e⌋=2, ⌊ -e⌋=-3, ⌊-π⌋=-4 )
The graph of floor function looks like steps. This is because for all values between two integers, the functions result would be one of those integers.
The empty circles indicate that the functions result, is not the same as where the empty circles are. For example, at (1) itself, the answer is no longer zero and is ( 1) instead. This wasn’t the case at,
For example:
( 0.999999 )
Ceiling function:
This function is denoted using ( “⌈…⌉” ) symbol, or brackets without the bent bottoms. It is the opposite of floor function, and rounds numbers up to their next integer. So if you have a positive number, the ceiling function returns its next integer. And if you have a negative number, the function removes the decimal and returns what’s left (basically next integer, meaning the bigger number. This can be a bit confusing in negative numbers).
For example:
(⌈2.1⌉=3, ⌈5.02⌉=6, ⌈-5.02⌉=-5, ⌈e⌉=3, ⌈-e⌉=-2, ⌈π⌉=4 )
The graph of ceiling function, also looks like steps. Compared to floor function, it is shifted to left by 1 unit, and switched the placement of filled and empty circles.
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