ALEKS Math FREE Sample Practice Questions

4- \(4a^2\sqrt{b} \)
\( \frac{\sqrt{32a^5 b^3}}{\sqrt{2ab^2} } = \frac{4a^2 \sqrt{2ab}}{b\sqrt{2a} } = 4a^2\sqrt{b} \) For additional educational resources, .

5- 57,000 loss
\(c(3)=(3)^2+10(3)+30=9+30+30=69 4×3=12⇒12-69=-57⇒57,000\) loss For additional educational resources, .

6- \(\frac{4}{5}\)
sinB\(=\frac{Opposite Side}{Hypotenuse}=\frac{4}{5}\) For additional educational resources, .

7- \(y=\frac{6}{7} x+\frac{12}{7}\)
\(-7y=-6x-12⇒y=\frac{-6}{-7} x-\frac{12}{-7}⇒y=\frac{6}{7} x+\frac{12}{7}\) For additional educational resources, .

8- \(0, -2, -3\)
Frist factor the function:
\(x (x+2)(x+3)\)
To find the zeros, \(f(x)\) should be zero.
\(f(x)=x (x+2)(x+3)=0\)
Therefore, the zeros are:
\(x=0\)
\((x+2)=0 ⇒ x= -2\)
\((x+3)=0 ⇒ x= -3\) For additional educational resources, .

9- \((1,4)\)
\(\begin{cases}5x+y=9\\10x-7y=-18\end{cases}\)⇒ Multiply the first equation by \(-2 ⇒ \begin{cases}-10x-2y=-18\\10x-7y=-18\end{cases}\) Add two equations \(⇒ -9y = -36 ⇒ y = 4\) then: \(x = 1\) For additional educational resources, .

10- 4
\((x – h)^2 + (y – k)^2 = r^2 ⇒\) center: (h,k) and radius: r
\((x – 3)^2 + (y + 6)^2 = 12 ⇒\) center: \((3,-6)\) and radius: \(\sqrt{16}=4\) For additional educational resources, .

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