7th Grade ACT Aspire Math Practice Test Questions
Preparing your student for the 7th Grade ACT Aspire Math test? Help your students build ACT Aspire Math test skills by following common 7th Grade ACT Aspire Math questions. Practicing common math questions is the best way to help your students improve their Math skills and prepare for the test. Here, we provide a step-by-step guide to solve 10 common 7th Grade ACT Aspire Math practice problems covering the most important math concepts on the 7th Grade ACT Aspire Math test. For additional educational resources, . For additional educational resources, visit the U.S. Department of Education website.
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p>A. 3 hours
B. 4 hours
C. 6 hours
D. 8 hours
7- 55 students took an exam and 11 of them failed. What percent of the students passed the exam?
A. \(20 \%\)
B. \(40 \%\)
C. \(60 \%\)
D. \(80 \%\)
8- Jason needs an \(75\%\) average in his writing class to pass. On his first 4 exams, he earned scores of \(68\%, 72\%, 85\%\), and \(90\%\). What is the minimum score Jason can earn on his fifth and final test to pass? __________
9- A bank is offering \(3.5\%\) simple interest on a savings account. If you deposit $12,000, how much interest will you earn in two years?
A. $420
B. $840
C. $4200
D. $8400
10- 5 less than twice a positive integer is 83. What is the integer?
A. 39
B. 41
C. 42
D. 44
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Answers:
1- C
\(4\%\) of the volume of the solution is alcohol. Let \(x\) be the volume of the solution.
Then: \(4\% \space of \space x = 24 \space ml ⇒ 0.04 x = 24 ⇒ x = 24 ÷ 0.04 = 600\)
2- C
Let \(x\) be the original price.
If the price of a laptop is decreased by \(10\%\) to $360, then:
\(90 \% of x=360 ⇒ 0.90x=360 ⇒ x=360÷0.90=400\)
3- B
Write the numbers in order:
\(4, 5, 8, 9, 13, 15, 18\)
Since we have 7 numbers (7 is odd), then the median is the number in the middle, which is 9.
4- A
Let \(L\) be the price of a laptop and \(C\) be the price of the computer.
\(3(L) =5(C) \space and \space L = $200 + C \)
Therefore, \(3($200 + C) =5C ⇒ $600 + 3C = 5C ⇒ C=$300\)
5- 97.6
Use the area of the square formula.
\(S = a^2 ⇒ 595.36 = a^2 ⇒ a = 24.4\)
Use the perimeter of the square formula.
\(P = 4a ⇒ P=4(24.4) ⇒ P = 97.6\)
6- C
The distance between Jason and Joe is 9 miles. Jason running at 5.5 miles per hour and Joe is running at the speed of 7 miles per hour. Therefore, every hour the distance is 1.5 miles less.
\(9 ÷ 1.5 = 6\)
7- D
The failing rate is 11 out of \(55 = \frac{11}{55}\).
Change the fraction to percent:
\(\frac{11}{55} ×100\%=20\%\)
20 percent of students failed. Therefore, 80 percent of students passed the exam.
8- 60
Jason needs an \(75\%\) average to pass for five exams. Therefore, the sum of 5 exams must be at least \(5 × 75 = 375\)
The sum of 4 exams is:
\(68 + 72 + 85 + 90 = 315\)
The minimum score Jason can earn on his fifth and final test to pass is:
\( 375 – 315 = 60\)
9- B
Use a simple interest formula:
\(I=prt\)
(I = interest, p = principal, r = rate, t = time)
\(I=(12000)(0.035)(2)=840\)
10- D
Let \(x\) be the integer. Then:
\(2x – 5 = 83\)
Add 5 both sides: \(2x = 88\)
Divide both sides by 2: \(x = 44\)
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