Top 10 4th Grade PARCC Math Practice Questions

B. \(90^\circ\)

C. \(180^\circ\)

D. \(240^\circ\)

7- Ella described a number using these clues:
Three-digit odd numbers that have a 6 in the hundreds place and a 3 in the tens place
Which number could fit Ella’s description?

A. 627

B. 637

C. 632

D. 636

8- Tam has 390 cards. He wants to put them in boxes of 30 cards. How many boxes does he need?

A. 7

B. 9

C. 11

D. 13

9- If this clock shows a time in the morning, what time was it 6 hours and 30 minutes ago?

A. 07:45 AM

B. 05:45 AM

C. 07:45 PM

D. 05:45 PM

10- Use the table below to answer the question.

The students in the fourth-grade class voted for their favorite sport. Which bar graph shows the results of the student’s votes?

A.

B.

C.

D.

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Answers:

1- 860
We round the number up to the nearest ten if the last digit in the number is 5, 6, 7, 8, or 9.
We round the number down to the nearest ten if the last digit in the number is 1, 2, 3, or 4.
If the last digit is 0, then we do not have to do any rounding, because it is already to the ten.
Therefore, the rounded number of 855 to the nearest ten is 860.

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2- A
\(\frac{12}{100}\) is equal to 0.12

3- A
7 days = 1 week
28 days \(= (28 ÷ 7)= 4\) weeks

4- C
Football teams should buy 14 uniforms and each uniform costs $24 so they should pay (14 \(×\) $24) $336.
Therefore, choice C is the correct answer:
\((24 × 10) + (24 × 4) =24(10+14) =24×14 = $336\)

5- C
These: \(98 – 31 = Z\)
\(98 – Z = 31\)
And \(Z + 31 = 98\) are equal.

6- A
This angle is less than \(90^\circ\). just choice A shows an angle less than \(90^\circ\).

7- B
Three–digit odd numbers that have a 6 in the hundreds place and a 3 in the tens place are 631, 633, 635, 637, 639. 637 is one of the alternatives.

8- D
Tam wants to divide his 390 cards into boxes of 30 cards. So he needs \(390÷30=13\) boxes.

9- C
Subtract hours: \(2 – 6 = -4\)
Subtract the minutes: \(15 – 30 = – 15\)
The minutes are less than 0, so:
• Add 60 to minutes ( \(-15 +60 =45\) minutes)
• Subtract 1 from hours \((-4 – 1 = -5)\) the hours are less than 0, add 24: \((24 – 5 =19)\)
The answer is 19:45 which is equal to 7:45

10- A

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