Peaks and Valleys: A Journey Through the Extreme Value Theorem

Consider the optimization of a solar panel’s efficiency. The goal is to maximize the panel’s energy output. By using the Extreme Value Theorem, engineers can determine the panel’s angle and orientation that yield the highest energy capture. This involves analyzing the function that relates the angle of the solar panel to the amount of absorbed solar energy. The theorem helps identify the optimal angle — the maximum point of the function — within a given range (e.g., 0 to 90 degrees), ensuring the solar panel operates at peak efficiency throughout the day. For additional educational resources,.

Let’s create a simplified numerical example for optimizing a solar panel’s efficiency. Suppose the energy output \( E \) of a solar panel, measured in kilowatt-hours, varies with its angle ( \theta ) (measured in degrees from the ground) according to the function:

\( E(\theta) = -2\theta^2 + 90\theta \)

This function might represent a simplified model where the energy output is maximal at a certain angle and decreases as the angle moves away from this optimal point. We’re interested in finding the angle that maximizes \( E \) within the practical range of \( 0^\circ \) to \( 45^\circ \).

1. Find the Critical Points: We first find the derivative of \( E(\theta) \) and set it to zero to find critical points. The derivative is:
   \( E'(\theta) = -4\theta + 90 \) Setting this equal to zero gives:
   \( -4\theta + 90 = 0 \)
   \( \theta = \frac{90}{4} = 22.5^\circ \)
2. Evaluate at Endpoints and Critical Point: We evaluate \( E \) at \( 0^\circ \), \( 22.5^\circ \), and \( 45^\circ \) to find which gives the maximum output. \( E(0) = -2 \times 0^2 + 90 \times 0 = 0 \) kilowatt-hours
   \( E(22.5) = -2 \times 22.5^2 + 90 \times 22.5=1012.5 \) kilowatt-hours
   \( E(45) = -2 \times 45^2 + 90 \times 45=0 \) kilowatt-hours

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Comparing these values, the maximum energy output of \( 1012.5 \) kilowatt-hours occurs at \( 22.5^\circ \). Therefore, in this simplified model, angling the solar panel at \( 22.5^\circ \) from the ground optimizes its energy capture, demonstrating an application of the Extreme Value Theorem in determining the most efficient operational angle.

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