How to Expand Sigma Notation?

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How to expand sigma notation: Start at the lower index, substitute each consecutive integer into the formula, and write every term through the upper index. Add the terms only when you also need the value of the sum.

Key takeaways:

  • The Greek letter (Sigma) means "add up."
  • Index variable (often (k) or (i)) tells you what changes; the lower bound is the start, the upper bound is the stop.
  • For consecutive integer indices with upper bound at least the lower bound, number of terms = upper bound − lower bound + 1.
  • To expand: substitute each integer value of the index into the formula, then add.
  • Sigma notation works for arithmetic and geometric series, polynomials, and any sum with a clear pattern.

The summation notation is useful for writing the sum of terms that follow a particular pattern. In this step-by-step guide, you will become more familiar with sigma notation along with how to write it.

Sigma conductor with train cars showing 3 + 5 + 7 = 15
Tutor-style math help

Expand Sigma Notation: what to notice and how to work it

Series skill

To expand a finite sigma sum, substitute every integer index from the lower limit through the upper limit and join the resulting terms with plus signs. Stop at the upper limit. Evaluating the sum is the separate step of adding those terms.

Read the limits first

In \(\sum_{k=1}^{3}(2k+1)\), the index takes the values 1, 2, and 3. There are three terms.

Avoid the off-by-one error

For consecutive integer indices from \(k=a\) through \(k=b\), with \(b\ge a\), the number of terms is \(b-a+1\). Include both endpoints.

Expand, then evaluate

Start at 1

\[\sum_{k=1}^{3}(2k+1)=(2\cdot1+1)+(2\cdot2+1)+(2\cdot3+1)=3+5+7=15.\]

First write the three substituted expressions. Simplify each term, then add if the question asks for the value.

Start somewhere else

\[\sum_{j=2}^{4}j^2=2^2+3^2+4^2=4+9+16=29.\]

The first index is 2, not 1. The letter j is a placeholder; changing it to k does not change the sum.

A reliable path

  1. List the indicesWrite the starting and ending integer values.
  2. Substitute carefullyReplace every occurrence of the index in the formula.
  3. Check the term countInclude the last term before simplifying or adding.
Try one before moving on

Expand \(\sum_{i=0}^{2}(i+4)\).

Answer: \((0+4)+(1+4)+(2+4)=4+5+6\). Its value is 15. Starting at zero still gives three terms.

The pop-up reviews prerequisite sequence and series ideas. For expansion practice, use the worked examples and original exercises below. Keep the formula and bounds visible while you write each term.

Further reading: OpenStax on series and summation notation.

The symbol (Σ) (Sigma) is generally used to indicate a sum of multiple terms. This symbol is generally associated with an index that varies to encompass all terms that must be considered in the sum.

Related Topics

A step by Step guide to Sigma notation

The sigma notation is the simplest way to write a very large set of elements in a sequence in a simple way. We know that a sequence is a set of terms that follow a pattern, and the Sigma notation is used to represent the sum of such elements.

This is also known as summation notation because it represents a sum. The terms that are being added in Sigma notation are called “summands” or “addends”.

In general, the summation notation is used to represent the sum of elements of a sequence \(\sum_{i=1}^{n}a_i\).

Summation symbol

The summation symbol is (∑) which is pronounced as “sigma”. This is a letter of the Greek alphabet. This sigma symbol is also known as the “capital sigma”. The summation notation written using the sigma symbol is also known as a “series” as it represents a sum.

writing sigma notation

Here are the steps in detail for writing the sum of terms as a summation:

  • Find the general term of the terms of the sum. If the sequence of expressions is arithmetic or geometric, we can use the general term formula of the respective sequences. Otherwise, we will find the general formula by examining and observing.
  • Select some letters of the alphabet (preferably lowercase letters) as the index. The common letters we choose for the index of summation are (i) or (k).
  • Observe the sequence and determine the first value and the last value of the index.
  • Finally, use the sigma symbol to write the sigma notation.

Expanding summation notation

Expanding the summation notation is just the opposite process of writing it. Here are the steps for writing the same.

  • Replace each index value (starting from the first to the last and increasing it by (1) every time) in the general term.
  • Place a plus symbol between all such terms obtained from the last step.
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Properties of Sigma notation

  1. A constant factor may move outside the sum: \(\sum_{i=1}^{n}ka_i=k\sum_{i=1}^{n}a_i\), where k does not depend on i.
  2. Addition and subtraction distribute across a finite sum: \(\sum_{i=1}^{n}(a_i\pm b_i)=\sum_{i=1}^{n}a_i\pm\sum_{i=1}^{n}b_i\).
  3. There is no general rule that splits a sum of products into a product of sums, or a sum of quotients into a quotient of sums. For example, \(1\cdot3+2\cdot4=11\), while \((1+2)(3+4)=21\).
  4. For a positive integer n, \(\sum_{i=1}^{n}1=n\).
  5. For a positive integer n, \(\sum_{i=1}^{n}0=0\).

Sigma Notation, Example 1:

Write the following sum in sigma notation: (5 + 10 + 20 + 40 + … + 1280).

Solution:

Every term is obtained by multiplying its previous term by (2). So it is a geometric sequence with a common ratio (r=2) and first-term (a = 5). So its general term is:

The general term is \(a_n=5\cdot2^{n-1}\). To find the last index, solve \(5\cdot2^{n-1}=1280\). Dividing by 5 gives \(2^{n-1}=256=2^8\), so n − 1 = 8 and n = 9.

So the given sum is \(\sum_{i=1}^{9}5\cdot2^{i-1}\). The index i appears in both the lower limit and the summand.

Exercises for Sigma Notation

solve each expression.

  1. Evaluate \(\sum_{k=1}^{4}3k\).
  2. Evaluate \(\sum_{n=2}^{5}n^2\).
  3. Write \(1-10+100-1000+10000\) in sigma notation.
  4. Write \(\frac14+\frac38+\frac7{16}+\frac{15}{32}+\frac{31}{64}\) in sigma notation.
Answers
  1. 30
  2. 54
  3. \(\sum_{k=1}^{5}(-10)^{k-1}\)
  4. \(\sum_{n=1}^{5}\frac{2^n-1}{2^{n+1}}\)

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Frequently Asked Questions

What does sigma notation mean?

Sigma notation uses the Greek capital letter (Sigma) to write a sum compactly. \(\sum_{k=1}^{n} a_k\) means “add up the terms (a_k) starting from (k=1) and ending at (k=n).” The variable (k) is the index of summation and steps up by 1 each term.

How do you read sigma notation?

Read \(\sum_{k=1}^{5} k^2\) as “the sum from (k=1) to (k=5) of (k) squared.” The lower-bound subscript tells you where the index starts. The upper-bound superscript tells you where it stops. The expression to the right is the formula to plug each index value into.

How do you expand sigma notation?

Substitute each integer index into the summand and write the terms with plus signs. For example, \(\sum_{k=1}^{4}(3k-1)=2+5+8+11\). Evaluating this expanded sum gives 26.

How many terms are in a sigma sum?

For consecutive integer indices from a through b, with b at least a, there are b − a + 1 terms. A sum from 3 through 8 has six terms; a sum from 1 through 10 has ten.

What is the index variable in sigma notation?

The placeholder that steps from the lower bound to the upper bound, one integer at a time. Common letters are (k), (i), (n), and (j). The choice is purely cosmetic, \(\sum_{k=1}^{5} k^2\) and \(\sum_{i=1}^{5} i^2\) mean exactly the same thing.

Can the lower bound of sigma notation be 0?

Yes. Many series start at 0, especially geometric series and Taylor series. \(\sum_{k=0}^{n} x^k = 1+x+x^2+\cdots+x^n\). The number of terms is still upper minus lower plus 1, so a sum from (k=0) to (k=n) has (n+1) terms.

What is the formula for the sum of the first n integers?

For a positive integer n, \(\sum_{k=1}^{n}k=\frac{n(n+1)}{2}\). For n = 100, this gives \(100\cdot101/2=5050\).

What is the formula for the sum of the first n squares?

For a positive integer n, \(\sum_{k=1}^{n}k^2=\frac{n(n+1)(2n+1)}{6}\). For n = 5, the value is 55, matching 1 + 4 + 9 + 16 + 25.

How do you handle a constant in sigma notation?

A constant pulls out front. \(\sum_{k=1}^{n} c = cn\) (you are adding (c) to itself (n) times). And \(\sum_{k=1}^{n} c\cdot a_k = c \sum_{k=1}^{n} a_k\), constants multiply the whole sum. These two rules show up constantly in series problems.

Where does sigma notation appear in math?

Arithmetic and geometric series, Taylor and Maclaurin series in calculus, Riemann sums for integrals, summation formulas in statistics (variance, expected value), and discrete probability. Once you start calculus, you will see sigma notation in almost every chapter.

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