Equation of Each Ellipse and Finding the Foci, Vertices, and Co– Vertices of Ellipses
To write the equation of an ellipse, we need the parameters that will be explained in this article.

An Ellipse is a closed curve formed by a plane. There are two types of ellipses: Horizontal and Vertical
- If major axis of an ellipse is parallel to \(x\), its called horizontal ellipse.
- If major axis of an ellipse is parallel to \(y\), its called vertical ellipse.
Step by Step Guide to Find Equation of Ellipses
The standard form of the equation of an Ellipse is:
- Horizontal: \(\color{blue}{\frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}=1}\)
- Vertical: \(\color{blue}{\frac{(x-h)^2}{b^2}+\frac{(y-k)^2}{a^2}=1}\)
The center is: \(\color{blue}{(h, k)}\)
The vertices are: \(\color{blue}{(h+a, k), (h-a, k)}\)
The foci are: \(\color{blue}{(h+c, k), (h-c, k)}\), where \(\color{blue}{c=\sqrt{a^2-b^2}}\)
The Values can be calculated according to the standard form of the equation of ellipses.

Equation of Each Ellipse and Finding the Foci, Vertices, and Co– Vertices of Ellipses – Example 1:
Find the center, vertices, and foci of this ellipse: \(\frac{(x-2)^2}{36}+\frac{(y+4)^2}{16}=1\)
Solution:
The standard form of the equation of an Ellipse is: \(\frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}=1\)
Then, \((h=2, k=-4, a=6, b=4)\).
So, the center is \((2, -4)\).
The vertices are \((h+a, k), (h-a, k) →(8, 4), (-4, 4)\)
Evaluate \(c\): \(c=\sqrt{a^2-b^2}\) \(=\sqrt{36-16}=2\sqrt{5}\)
Then the foci are \((2+2\sqrt{5}, -4)\) and \((2-2\sqrt{5}, -4)\).
Exercises for Equation of Finding the Foci, Vertices, and Co– Vertices of Ellipses
Find the center, vertices, and foci of each ellipse.
- \(\color{blue}{9x^2+4y^2=1}\)
- \(\color{blue}{16x^2+25y^2=100}\)
- \(\color{blue}{25x^2+4y^2+100x-40y=400}\)
- \(\color{blue}{\frac{(x-1)^2}{9}+\frac{y^2}{5}=100}\)

- \(\color{blue}{Center: (0, 0), Vertices: (0,\frac{1}{2}), (0, -\frac{1}{2}), foci: (0, \frac{\sqrt{5}}{6}), (0, -\frac{\sqrt{5}}{6})}\)
- \(\color{blue}{Center: (0, 0), Vertices: (\frac{5}{2}, 0), (-\frac{5}{2}, 0), foci: (\frac{3}{2}, 0), (-\frac{3}{2}, 0)}\)
- \(\color{blue}{Center: (-2, 5), Vertices: (-2,5+5\sqrt{6}), (-2, 5-5\sqrt{6}), foci: (-2, 5+3\sqrt{14}), (-2, 5-3\sqrt{14})}\)
- \(\color{blue}{Center: (1, 0), Vertices: (31, 0), (-29, 0), foci: (21, 0), (-19, 0)}\)
Related to This Article
More math articles
- A Deep Dive Into The World Of Limits: Limit Laws
- 6th Grade AZMerit Math Worksheets: FREE & Printable
- How to Solve Word Problems Involving the Percentage of a Number?
- What Skills Do I Need for the TASC Math Test?
- 8th Grade MCA Math Worksheets: FREE & Printable
- 10 Most Common SSAT Middle Level Math Questions
- Is ALEKS just for Mathematics?
- SSAT Lower Level Math Practice Test Questions
- What Does the CBEST Test Qualify You For?
- The 5 BEST Online Math Tutoring Tools
What people say about "Equation of Each Ellipse and Finding the Foci, Vertices, and Co– Vertices of Ellipses - Effortless Math: We Help Students Learn to LOVE Mathematics"?
No one replied yet.