Equation of Each Ellipse and Finding the Foci, Vertices, and Co– Vertices of Ellipses
To write the equation of an ellipse, we need the parameters that will be explained in this article.

An Ellipse is a closed curve formed by a plane. There are two types of ellipses: Horizontal and Vertical
- If major axis of an ellipse is parallel to \(x\), its called horizontal ellipse.
- If major axis of an ellipse is parallel to \(y\), its called vertical ellipse.
Step by Step Guide to Find Equation of Ellipses
The standard form of the equation of an Ellipse is:
- Horizontal: \(\color{blue}{\frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}=1}\)
- Vertical: \(\color{blue}{\frac{(x-h)^2}{b^2}+\frac{(y-k)^2}{a^2}=1}\)
The center is: \(\color{blue}{(h, k)}\)
The vertices are: \(\color{blue}{(h+a, k), (h-a, k)}\)
The foci are: \(\color{blue}{(h+c, k), (h-c, k)}\), where \(\color{blue}{c=\sqrt{a^2-b^2}}\)
The Values can be calculated according to the standard form of the equation of ellipses.

Equation of Each Ellipse and Finding the Foci, Vertices, and Co– Vertices of Ellipses – Example 1:
Find the center, vertices, and foci of this ellipse: \(\frac{(x-2)^2}{36}+\frac{(y+4)^2}{16}=1\)
Solution:
The standard form of the equation of an Ellipse is: \(\frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}=1\)
Then, \((h=2, k=-4, a=6, b=4)\).
So, the center is \((2, -4)\).
The vertices are \((h+a, k), (h-a, k) →(8, 4), (-4, 4)\)
Evaluate \(c\): \(c=\sqrt{a^2-b^2}\) \(=\sqrt{36-16}=2\sqrt{5}\)
Then the foci are \((2+2\sqrt{5}, -4)\) and \((2-2\sqrt{5}, -4)\).
Exercises for Equation of Finding the Foci, Vertices, and Co– Vertices of Ellipses
Find the center, vertices, and foci of each ellipse.
- \(\color{blue}{9x^2+4y^2=1}\)
- \(\color{blue}{16x^2+25y^2=100}\)
- \(\color{blue}{25x^2+4y^2+100x-40y=400}\)
- \(\color{blue}{\frac{(x-1)^2}{9}+\frac{y^2}{5}=100}\)

- \(\color{blue}{Center: (0, 0), Vertices: (0,\frac{1}{2}), (0, -\frac{1}{2}), foci: (0, \frac{\sqrt{5}}{6}), (0, -\frac{\sqrt{5}}{6})}\)
- \(\color{blue}{Center: (0, 0), Vertices: (\frac{5}{2}, 0), (-\frac{5}{2}, 0), foci: (\frac{3}{2}, 0), (-\frac{3}{2}, 0)}\)
- \(\color{blue}{Center: (-2, 5), Vertices: (-2,5+5\sqrt{6}), (-2, 5-5\sqrt{6}), foci: (-2, 5+3\sqrt{14}), (-2, 5-3\sqrt{14})}\)
- \(\color{blue}{Center: (1, 0), Vertices: (31, 0), (-29, 0), foci: (21, 0), (-19, 0)}\)
Related to This Article
More math articles
- How to Graph Inverse Trigonometric Functions?
- Top 10 3rd Grade PARCC Math Practice Questions
- How to Determine Limits Using the Squeeze Theorem?
- FREE 8th Grade SBAC Math Practice Test
- 4th Grade OST Math Practice Test Questions
- How to Use Integers to Complete Equations
- How to Find Factors of Numbers?
- 6th Grade ACT Aspire Math FREE Sample Practice Questions
- FREE 6th Grade MAP Math Practice Test
- Full-Length 6th Grade ACT Aspire Math Practice Test
What people say about "Equation of Each Ellipse and Finding the Foci, Vertices, and Co– Vertices of Ellipses - Effortless Math: We Help Students Learn to LOVE Mathematics"?
No one replied yet.