Divisibility Rules

Definitionnoun phrase

What are divisibility rules?

Divisibility rules are shortcuts that tell whether one whole number divides another with no remainder, without doing the division. A number is divisible by 2 if its last digit is even, by 3 if its digit sum is divisible by 3, by 5 if it ends in 0 or 5, and by 10 if it ends in 0.

In Spanish
reglas de divisibilidad
Also called
divisibility tests, rules of divisibility, divisibility tricks
Grade level
K-5
Grade 4Grade 5Grade 6CCSS 4.OA.B.4TABEASVABGEDHiSET

Divisibility Rules in a picture

Table of divisibility rules for 2, 3, 4, 5, 6, 8, 9 and 10A table with one row per divisor: 2, last digit even; 3, digit sum divisible by 3; 4, last two digits divisible by 4; 5, last digit 0 or 5; 6, divisible by 2 and 3; 8, last three digits divisible by 8; 9, digit sum divisible by 9; 10, last digit 0. Each row has an example.Divisibility rulesbytestexample2last digit is even (0, 2, 4, 6, 8)7,3583digit sum divisible by 3471: 4+7+1=124last two digits divisible by 43,716: 165last digit is 0 or 59856divisible by 2 and by 36428last three digits divisible by 85,120: 1209digit sum divisible by 9738: 7+3+8=1810last digit is 04,090Digit-sum rules (3, 9) look at all digits;last-digit rules (2, 4, 5, 8, 10) only at the end.
Each divisibility rule checks a small piece of the number instead of dividing the whole thing.

Formal definition and notation

A whole number n is divisible by d ≠ 0 when n = d × k for some whole number k, written d ∣ n. Divisibility rules follow from place value: since 10 leaves remainder 1 when divided by 3 or 9, n and its digit sum leave the same remainder, and since 100 is divisible by 4 and 1,000 by 8, only the last two or three digits decide divisibility by 4 or 8.

Symbol Read it as Meaning
d ∣ n d divides n n is divisible by d: 3 ∣ 471

Key facts

  • By 2: last digit 0, 2, 4, 6 or 8. By 5: last digit 0 or 5. By 10: last digit 0.
  • By 3: the digit sum is divisible by 3. By 9: the digit sum is divisible by 9. Example: 5,832 has digit sum 18, so it is divisible by both.
  • By 4: the last two digits form a number divisible by 4. By 8: the last three digits do.
  • By 6: divisible by both 2 and 3. Combine rules for other products of different primes, like 15 = 3 × 5.
  • By 11: alternately subtract and add the digits; if the result is divisible by 11, so is the number. For 2,728: 2 − 7 + 2 − 8 = −11.
  • By 7: double the last digit and subtract it from the rest; repeat. For 343: 34 − 6 = 28, and 28 is divisible by 7.

Try it: check your divisibility test

Interactive

Apply a rule in your head, then type the number to see its full list of factors. Try 2,736 (digit sum 18) and 1,001 (divisible by 7, 11 and 13).

This interactive needs JavaScript. The worked examples below show the same ideas step by step.

Divisibility Rules examples, step by step

Example 1: Test 2,345

Warm-up

Is 2,345 divisible by 2, 3, 5 or 10?

  1. Last digit 5 is odd: not divisible by 2 or 10.
  2. Last digit 5: divisible by 5.
  3. Digit sum 2 + 3 + 4 + 5 = 14, not a multiple of 3: not divisible by 3.

Answer: 2,345 is divisible by 5 only (of 2, 3, 5 and 10).

Example 2: Find the missing digit

Core

What digit can replace the box in 4,7□ 2 so the number is divisible by 9?

  1. Known digit sum: 4 + 7 + 2 = 13.
  2. The full sum must be a multiple of 9: 18 is the only one possible, since the box is 0 to 9.
  3. Box = 18 − 13 = 5. Check: 4,752 ÷ 9 = 528.

Answer: The digit is 5, making 4,752.

Example 3: Divisible by 12?

Test-style

Is 9,516 divisible by 12?

  1. 12 = 3 × 4, and 3 and 4 share no factor, so test both.
  2. By 4: last two digits 16, and 16 ÷ 4 = 4. Yes.
  3. By 3: 9 + 5 + 1 + 6 = 21, a multiple of 3. Yes.
  4. So 9,516 is divisible by 12: 9,516 ÷ 12 = 793.

Answer: Yes, 9,516 is divisible by 12.

Common mistakes

✗ Mistake316 is divisible by 3 because it ends in 6.
✓ InsteadDigit sum 3 + 1 + 6 = 10, not a multiple of 3, so 316 is not divisible by 3.

The rule for 3 uses the digit sum, not the last digit.

✗ Mistake1,324 is divisible by 8 because 24 is divisible by 8.
✓ InsteadUse the last three digits: 324 ÷ 8 = 40.5, so 1,324 is not divisible by 8.

The test for 4 uses two digits; the test for 8 needs three.

✗ Mistake24 is divisible by 2 and 4, so every number divisible by 2 and 4 is divisible by 8.
✓ Instead12 is divisible by 2 and 4 but not by 8.

Combining rules only works for factors that share no common factor, like 3 and 4 for 12.

Not to be confused with

Divisibility Rulesvs.Divisor

A divisor is the number you divide by. A divisibility rule is a quick test of whether that divisor goes in evenly.

Divisibility Rulesvs.Factor

If a number is divisible by 6, then 6 is a factor of it. Divisibility rules are a fast way to find factors.

Quick check: 3 questions

Question 1 of 3

Which number is divisible by 9?

Show answer and explanation

Answer: A. 4,518 has digit sum 4 + 5 + 1 + 8 = 18, a multiple of 9. The others have digit sums 19, 10 and 15; 6,135 is divisible by 3 (15) but not by 9.

Question 2 of 3

Which number is divisible by 6?

Show answer and explanation

Answer: C. 5,412 is even and its digit sum 5 + 4 + 1 + 2 = 12 is a multiple of 3. 3,124 is even but its digit sum is 10; 2,715 and 4,503 are odd.

Question 3 of 3

A number ends in 30. Which must be true?

Show answer and explanation

Answer: D. Any number ending in 0 is divisible by 10 (and 2 and 5). It need not be divisible by 4 (130 is not), 3 (130 is not) or 9.

Divisibility Rules: frequently asked questions

Why does the divisibility rule for 3 work?

Each place value is 1 more than a multiple of 3: 10 = 9 + 1, 100 = 99 + 1, 1,000 = 999 + 1. So 471 is 4 × 99 + 7 × 9, which is a multiple of 3, plus 4 + 7 + 1. The number is divisible by 3 exactly when that digit sum is. The same reasoning gives the rule for 9.

Is there a divisibility rule for 7?

Yes, though it is slower than dividing for small numbers. Double the last digit and subtract it from the number formed by the other digits; repeat until the result is small. If the result is divisible by 7, so is the original. For 637: 63 − 14 = 49, and 49 = 7 × 7, so 637 is divisible by 7.

Practice and tools

Sources

  1. Common Core State Standards, Grade 4 Operations and Algebraic Thinking (4.OA.B.4)
  2. OpenStax, Prealgebra 2e, 2.4 Find Multiples and Factors

Updated November 2026·Reviewed by the Effortless Math team·Standards: CCSS 4.OA.B.4

Cite this entry

Effortless Math Team. “Divisibility Rules.” Effortless Math Dictionary. Updated November 2026. https://www.effortlessmath.com/math-dictionary/divisibility-rules/

Flashcard

TermDivisibility Rulesby 3? add the digits
DefinitionQuick tests for dividing evenly. Ends in 0 or 5: divisible by 5. Digit sum a multiple of 3: divisible by 3, as with 471.
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